What is the formula for a trianglar prism?

Based on information from Harper’s Index, 37% of adult Americans believe in Extraterrestrials. Out of a random sample of 100 adu

san4es73 [151]

Answer:

z(s) is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

Step-by-step explanation:

We have a prortion test.

P₀ = 37 % P₀ = 0,37

sample size = n = 100

P sample proportion = P = 47 % P = 0,47

confidence interval 95 %

α = 0,05

One tail-test (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.

1.-Hypothesis:

H₀ null hypothesis P₀ = 0,37

Hₐ alternative hypothesis P₀ > 0,37

2.-Confidence interval 95 %

α = 0,05 and z(c) = 1.64

3.-Compute of z(s)

z(s) = [ P - P₀ ] /√(P₀Q₀/n) ]

z(s) = [ ( 0,47 - 0,37 ) / √0.37*0,63/100

z(s) = 0,1 /√0,2331/100 ⇒ z(s) = 0,1 /0,048

z(s) = 2.08

4.-Compare z(s) and z(c)

z(s) > z(c) 2.08 > 1.64

5.-Decision:

z(s) is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

5 0

4 years ago

Which of the graphs below would result if you made the leading term of the

Anettt [7]

Answer:

A%7.2= ( 7.5№) =(+--+) this is the best answer

3 0

3 years ago

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Solve for x: -a + 3b > 5

Viefleur [7K]

Theres an app called photomath thats useful for these kinds of problems

8 0

3 years ago

A group fitness gym classifies its fitness class attendees by class type and member status. The marketing team has gathered data

PilotLPTM [1.2K]

The probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class is 0.009.

<h3>What is the probability?</h3>

Probability refers to a possibility that deals with the occurrence of random events.

The marketing team has gathered data from a random month, in which there were 2039 class attendees.

The probability that a class attendee is a non-member of the gym and is attending a barre class

= 185/2039

= 0.09

The probability that a class attendee is a member of the gym and is attending a boot camp class

= 204/2039

= 0.10004

The probability for both the event would be

= 0.09 x 0.10004

= 0.009

Learn more about probability here;

brainly.com/question/11234923

#SPJ1

8 0

3 years ago

What is the area of this figure?

lesantik [10]

Answer:

$\Huge\boxed {A =859ft^{2} }$

Step-by-step explanation:

Hello There!

To solve for the area of this figure we need to split the figure into 3 different parts:

A rectangle with a length of 9 ft and a width of 7 ft

a rectangle with a width of 9ft + 7ft and a length of 25 ft

a rectangle with a width of 18 ft and a length of 22 ft

To find the area of a rectangle we use the formula

$A=w*l$ where w = width and l = length

for the first one we plug in the values

A = 9 * 7

9 * 7 = 63 so the area of the smallest rectangle is 63ft²

Now lets find the area of the larger rectangle

The dimensions are l = 25 ft and w = 9 + 7 (16 ft)

Now we can plug in the values into the area formula

A = 16 * 25

16*25=400 so the area of the larger rectangle is 400 ft²

Now lets find the area of the last rectangle

The dimensions are l = 22 ft and w = 18 ft

now lets plug in the values to the formula

A = 22 * 18 =396

so the area of the last rectangle is 396 ft²

Finally we want to add all of the areas together

396 + 400 + 63 = 859

So the area of the figure is 859 ft²

7 0

3 years ago

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