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dusya [7]
3 years ago
12

BRAINLIEST!!PLEASE HELP ME!

Mathematics
2 answers:
Andru [333]3 years ago
8 0
Easiest way I could think of is choose a point in the gray area and use the X,Y to plug into the answers whichever one makes sense is correct.
DiKsa [7]3 years ago
8 0
The answer is b I just graphed it on Desmos
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Complete the definition of the piecewise defined
Westkost [7]

Answer: a=1 b=3

Step-by-step explanation: the x for each of the points are 1 and 3

7 0
3 years ago
Solve each question. Solve for x
mamaluj [8]
I hope this helps you

3 0
3 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Solve the equation below<img src="https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B27%28x-2%29%7D%3D3" id="TexFormula1" title="\sqrt[5]{
Mariana [72]

Answer:

x = 11

Step-by-step explanation:

Raising both sides to the fifth power, we get:

27(x - 2) = 3⁵

x - 2 = 3⁵ / 27

x - 2 = 3⁵ / 3³

x - 2 = 3⁽⁵⁻³⁾ = 3² = 9

x = 11

8 0
4 years ago
What is the answer what should I write down I will mark you the Brainlyiest 40 points so do it good!
Leni [432]
First you can count multiples of 7 all the way up to 84. 7,14,21,28,35,42,49,56,63,70,77,and 84.
Or you can do 7 x 12 equals 84.
Second write down the long division way 84/7.
7 goes into 8 one time write 7 at the top then write one at the bottom bring down the 4 and make it 14
you know 7 x 2 = 14 so 12 x 7 equals 14.
8 0
4 years ago
Read 2 more answers
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