Answer:
![\sqrt[n]{x} => n \ is \ the \ index \ and \ x \ is \ the \ radicand\\\\1. b) -23^7\\\\2. a) 2\\\\3. b) \sqrt{3} \cdot\sqrt{2} =\sqrt{6}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%3E%20%20n%20%5C%20is%20%5C%20the%20%5C%20index%20%5C%20and%20%5C%20x%20%5C%20is%20%5C%20the%20%5C%20radicand%5C%5C%5C%5C1.%20b%29%20%20-23%5E7%5C%5C%5C%5C2.%20a%29%202%5C%5C%5C%5C3.%20b%29%20%5Csqrt%7B3%7D%20%5Ccdot%5Csqrt%7B2%7D%20%3D%5Csqrt%7B6%7D)
For q1 and q2 I have given explanation already.
q3 to multiply radicals the index must be same.
option a . different index. ∛5 √2
option b . same index so √3 √2 = √6
option c. again different index.
Answer:
h=6
Step-by-step explanation:
h/8=12/16
16h=96
h=6
For this case we have that by definition of power properties it is fulfilled that:

Then, if we have the following expression:

Applying the property, we can rewrite the expression as:

Answer:
