As you move across the period on the periodic table what pattern can be described about the electron configurations?
1 answer:
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Answer:
C. 2.
Explanation:
The total reaction order of this reaction is second order (2). For a second order reaction ,the rate depends on two variable concentration terms which may or may not be same.
Given that:
Two reactants combine to form a product in the reaction A + B → C
The above reaction is bimolecular as two molecules are involved in the reaction.
If and
are the concentrations of A and B respectively at any time t, then assuming that the reaction is of first order with respect to both A and B , the overall order is second and the reaction rate is given by:
where;
= specific rate constant for a second order reaction and becomes the rate of the reaction when both
and
are unity.
Answer:
The bands are due to:
λmax = 289 nm n→π* transition (E = 12)
λmax = 182 nm π→π* transition (E=10000)
Explanation:
The two types of acetaldehyde transition are as follows:
n→π* and π→π*
From the attached diagram we have to:
ΔEn→π* < ΔEπ→π*
ΔEα(1/λ)
Thus:
λn→π* > λπ→π*
In n→π* spin forbidden, the intensity is low. Thus, the molar extinction E for n→π* is very low.
The same way, for π→π* spin allowed the intensity is high. Thus, the molar extinction coefficient E for π→π* is high too.
The bands are due to:
λmax = 289 nm n→π* transition (E = 12)
λmax = 182 nm π→π* transition (E=10000)
