Question

A rectangle has coordinates A(-4?4), B(0,0), C(6,8), and D(2,11) what is the area of the rectangle

Answer 1

Answer:

The area of the rectangle is 56

Step-by-step explanation:

Thank you for this question.

find the distance between AB and BC

the formula for that is $\sqrt{(x2-x1)^2+(y2-y1)^2}$

lets do this first

$AB=\sqrt{((0--4)^2+(0-4)^2)} \\AB=\sqrt{4^2+(-4)^2} \\AB=\sqrt{16+16} \\AB=\sqrt{32} \\AB=5.6\\\\BC=\sqrt{(0-6)^2+(0.8)^2}\\BC=\sqrt{(-6)^2+(-8)^2}\\BC=\sqrt{36+64}\\BC=\sqrt{100}\\BC=10$

Now multiply the lengths of AB and BC

10*5.6=56

The area of the rectangle is 56

Hope this helps :)