Answer:
A boy can write one page in one minute
Answer: * = 36x^2
Note: Im guessing you're here for rsm struggles. That's how I found this question. I searched the web for the answer to this rsm problem, but I couldnt find it. I was happy to find this brainly link, but annoyed to find it was unanswered. I did the problem, and now i'll help future rsm strugglers out. Thanks for posting this question.
Step-by-step explanation:
Ok, so we know that trinomials like this are squares of binomials. this in mind, we know that it can also be written as (x+y)^2. (also brainly's exponents feature used to be better, if the exponents are confusing you, comment.) Using the (x+y)^2 equation, you know that by simplifying it, you get x^2+2xy+y^2. Basically we're looking for x^2. Using the middle term, 2xy, or 12x in this equation, we can find x. since we know the square root of 1 is 1, we know 12=2x. This is kinda confusing, but basically since the answer is 6, we know that the x-term is 6x. We square 6x and get 36x^2. guaranteed to work on the rsm student portal, i'm in rsm and i just answered this question.
Hope this helps! Also, im not usually too active on brainly unless im looking for HW answers, so if you understand this explanation and you see a confused comment, help out a friend and answer it. Happy holidays!
Answer:
Step-by-step explanation:
Hello!
For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.
In this example the variable is:
X: height of a college student. (cm)
There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.
The option you have is to apply the Central Limit Theorem.
The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.
As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.
The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:
X[bar]~~N(μ;σ2/n)
Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:
98% CI
1 - α: 0.98
⇒α: 0.02
α/2: 0.01

X[bar] ± 
174.5 ± 
[172.22; 176.78]
With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].
I hope it helps!
Answer:
Step-by-step explanation:
I'll draw a quick sketch. It's hard to "see" this kinda of problem w/o a drawing , so start there. just draw as much as you can from what the problem tells you.
diameter = 14 cm
radius = 7 cm
pi = 3.142
PRQ = 35 °
to find Y use law of sines
sin(70) / Y = sin(55) / 7
sin(70) / sin(55) / 7 = Y ( I'll use my calculator for all the non standard angles )
sin(70) * 7 / sin(55) = Y ( and invert and multiply the fraction in the denom )
8.03007 = Y
x = 70 °
if you have questions, and you should, just put them in the comments , I'll see them later :)