The dimensions of the rectangular area of Tina's fence is 40 ft by 40 ft
<h3 />
<h3>Area of a rectangle:</h3>
where
l = length
w = width
She wants to create a rectangular area of 1,600 square feet for her pet . Therefore,
lw = 1600
Therefore,
perimeter = 160 ft
Then,
perimeter of rectangle = 2(l + w)
160 = 2(l + w)
l + w = 80
Let's combine the equations
lw = 1600
l + w = 80
l = 80 - w
Therefore,
w(80 - w) = 1600
80w - w² = 1600
Therefore,
w² - 80w + 1600 = 0
w² - 40w - 40w + 1600 = 0
w(w - 40) - 40(w - 40) = 0
(w - 40)(w - 40) = 0
w = 40 or 40
Therefore, the dimensions can be calculated as follows:
lw = 1600
40l = 1600
l = 1600 / 40
l = 40 ft
Therefore, the dimensions are 40ft by 40 ft
learn more on algebraic model here: brainly.com/question/4151078
Answer:
Step-by-step explanation:
F(x)=2x^2+5x-16 for x=4
90/4 = 22.5
176/4=44
65/4=16.25
A. 22.5 CM tall, 44 CM wide and 65 CM deep
Answer:
The answer is a, 8+s=10
Step-by-step explanation:
Pretty sure it would be A
