Answer:
25km/hr (take the word train as bus )
Step-by-step explanation:
Answer
Let x km/hr be the constant speed of the train,
Then Time taken to cover 300km=
x
300
hrs
Time taken to cover 300km when the speed is increased by 5km/hr=
x+5
300
hours
It is given that the time to cover 300km is reduced by 2 hours
∴
x
300
−
x+5
300
=2
⇒
x(x+5)
300(x+5)−300x
=2⇒2x
2
+10x=1500
⇒x
2
+5x−750=0⇒x
2
+30x−25x−750=0
⇒(x+30)(x−25)=0⇒x=25orx=−30
But x cannot be negative. Therefore x=25
Hence, the original speed of the train is 25km/hr
Answer:
Solve for y by simplifying both sides of the equation, then isolating the variable.
Exact Form:
y = 5
/2
Decimal Form:
y = 2.5
Mixed Number Form:
y = 2 and 1
/2
Step-by-step explanation:
Hope this helps! Have a great day!
I believe that the answer is b
Answer:
C. 2
Step-by-step explanation:
If the discriminant is >0 we have 2 real solutions
If the discriminant is =0 we have 1 real solutions
If the discriminant is <0 we have 2 complex solutions (no real solutions)
since 10>0 we have 2 real solutions
