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shtirl [24]
3 years ago
9

"Express as a mixed numeral: 39/8" is a problem found in a fifth-grade arithmetic textbook. This problem is BEST solved through:

Please choose the correct answer from the following choices, and then select the submit answer button.
a.trial and error.
b.insight.
c.an algorithm.
d.a heuristic.
Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Answer:

  c.  an algorithm

Step-by-step explanation:

Most math problems are best solved using an algorithm. Certainly, converting numbers from one form to another is easily done that way.

_____

The integer part is the whole-number quotient of the division. The fractional part is the remainder divided by the denominator:

  39/8 = 32/8 + 7/8 = 4 7/8

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Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 100(1.21)x = 110
SVETLANKA909090 [29]

Answer:X=110/121

Step-by-step explanation:

Multiply 100 by 1.21 then by x

121x=110

Divide both side by 121

X=110/121

X=0.91

8 0
3 years ago
Find the first four terms of the sequence given a1=18 and an+1=2+an/2.
EleoNora [17]

Answer:

Step-by-step explanation:

hello

a_1=18\\\\a_2=2+\dfrac{a_1}{2}=2+\dfrac{18}{2}=2+9=11\\\\a_3=2+\dfrac{a_2}{2}=2+\dfrac{11}{2}=\dfrac{4+11}{2}=\dfrac{15}{2}\\\\a_4=2+\dfrac{a_3}{2}=2+\dfrac{15}{2}=\dfrac{4+15}{2}=\dfrac{19}{2}

hope this helps

7 0
3 years ago
Read 2 more answers
The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.
Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

V=\frac{4}{3}  \pi r^3

Substituting \pi=3.14 and r=5 , we get,

V=\frac{4}{3} (3.14)(125)

V=\frac{1580}{3}

V=523.3333 \ in^3

Rounding off to two decimal places, we have,

V=523.33 \ in^3

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = \frac{3}{4} (5)=3.75

Radius of the third sphere = \frac{3.75}{2} =1.875

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

V=\frac{4}{3}  \pi r^3

Substituting \pi=3.14 and r=1.875 , we get,

V=\frac{4}{3} (3.14)(1.875)^3

V=\frac{4}{3} (3.14)(6.59)

V=27.5901 \ in^3

Rounding off to two decimal places, we have,

V=27.59 \ in^3

Thus, the volume of the third sphere is 27.59 in³

4 0
4 years ago
10 cookies 4 chocolate chip 3 are peanut butter 3 are sugar what fraction of the cookies are chocolate chip
Lilit [14]
4/10 cookies so that is 2/5 or 40% :)
7 0
3 years ago
2 - 1 and 3/8 I don't know but I think it is 1 and 3/8 lol
Lubov Fominskaja [6]
Yea you are right it is right
5 0
3 years ago
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