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horsena [70]
3 years ago
7

P(z=1.85) what is the area to the left of z= 1.85

Mathematics
1 answer:
Kisachek [45]3 years ago
7 0
0.84(because 20% of the observations are about 0.84)
You've found the 80th percentile! The 80th percentile of the standard normal distribution is 0.84. That's because 80% of the observations fall below 0.84. (Note: The 80th percentile of every normal distribution is 0.84 times the standard deviation above the mean.)

 


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Find the average rate of change for f(x) = x2 + 9x + 18 from x = -10 to x = 10.
Ratling [72]
With the way the equation is written, we can assume that the “x2” is x multiplied by 2.

The x2 and 9x are like terms, and can be simplified to 11x.

Our new equation is
f(x) = 11x + 18

With no exponential functions in the equation, the difference of each value’s output would be 11.
4 0
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Which of the following is a rational number?<br> 148, 49, 50, 51
Katarina [22]

Answer:

50 is the answer because you can divide 2 numbers to get this number.

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Which expressions are difference of squares?
cluponka [151]

Answer:

x² - y² and x^4 - 36

Step-by-step explanation:

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6 0
3 years ago
Show work and graph it
jarptica [38.1K]
The answer to the question

4 0
3 years ago
On the kite, vertex A at the top, vertex B at the right, vertex C at the bottom, and vertex D at the left. Side A B is marked co
bazaltina [42]

Answer:

Part 1) m\angle 1=39^o

Part 2) m\angle 3=51^o

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the measure of angle 1

we know that

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That means

m\angle 1=39^o

In this problem the longer diagonal is the segment AC

Part 2) Find the measure of angle 3

we know that

The intersection of the diagonals of a kite form 90 degrees.

That means ----> The triangle ADO (O is the intersection point both diagonals) is a right triangle

so

39^o+m\angle 3=90^o ----> by complementary angles in a right triangle

m\angle 3=90^o-39^o=51^o

8 0
3 years ago
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