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Inga [223]
2 years ago
5

Harry solves the equation 1/3t = 15. He says the solution is 30. Is his answer correct? Fill in the blanks to explain how Harry

can check whether his solution is correct.
Harry can first substitute _______ for t. He can then multiply 1/3 by _______ to get a product of ______. Since 15 ________ equal to _______, Harry’s solution _______ correct.
Mathematics
1 answer:
aksik [14]2 years ago
5 0

Harry can first substitute 30 for t

He can then multiply \frac{1}{3} by 30 to get a product of 10

Since, 10 is not equal to 15, Harry's solution is not correct.

<em><u>Solution:</u></em>

Given that,

Harry solves the equation:

\frac{1}{3}t = 15

He says the solution is 30

We have to check if his answer is correct or not

<em><u>Fill in the blanks to explain how Harry can check whether his solution is correct</u></em>

Harry can first substitute 30 for t

\frac{1}{3} \times 30 = 15

He can then multiply \frac{1}{3} by 30 to get a product of 10

10\neq 15

Since, 10 is not equal to 15, Harry's solution is not correct

<em><u>Correct solution:</u></em>

\frac{1}{3}t = 15\\\\t = 15 \times 3\\\\t = 45

Thus correct solution is 45

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Jamie wants to build a rectangular fence around a new garden. He can afford at most 70
KonstantinChe [14]

Option B is correct. <em>Yes,</em><em> (9, 22) is a solution to the </em><em>inequalities</em><em> and the</em><em> measurements</em><em> will fit in the space. </em>

The formula for calculating the perimeter of the rectangular fence is expressed as:

A = 2(L + W) where:

L is the length

W is the width

If Jamie can afford at most 70feet to build a rectangular fence is expressed as:

2L + 2W ≤ 70

<em>We are to check if the garden measure 9 feet by 22 feet. To do this we are to substitute L = 9 and W = 22 into the formula to check if the result will be less than 70</em>

On substituting:

= 2(9) + 2(22)

= 18 + 44

= 62 feet

Since 63 feet is less than 70 feet, hence we can conclude that <em>Yes,</em><em> (9, 22) is a solution to the </em><em>inequalities</em><em> and the</em><em> measurements</em><em> will fit in the space. </em>

<em />

<em>Learn more here: brainly.com/question/17229451</em>

8 0
2 years ago
A new photocopier works 4 times as fast as an old one. When the machines work together, a university can produce all its staff m
Usimov [2.4K]

The old photocopier can make x manuals in an hour. The new photocopier can make 4x. Combined, they made 5x manuals in an hour.

In one hour they can make 1/28 of the manuals.

1/(28*5)=1/140 is the rate.

The new photocopier can make all the manuals in 4/140 or 35 hours.

The old one can make them in 140 hours.

6 0
2 years ago
Car A has an initial value of 30,000 and depreciates at a rate of 20% per year. Car B has an initial value of 20,000 and depreci
Doss [256]

Answer:

The value of Car B will become greater than the value of car A during the fifth year.

Step-by-step explanation:

Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.

In the attached excel file, the following are used:

Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000

Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000

Annual Depreciation expense of Car B in Year 7 =  Beginning value of Car B in Year 7 = 2,000

Conclusion

Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.

Download xlsx
4 0
2 years ago
Read 2 more answers
Please solve these 3 questions
ivolga24 [154]

Answer:

oh you do 3 - 8 witch equals -3=x minus 6 = -9

Step-by-step explanation:

hope this helps

5 0
2 years ago
We can describe 15x-10 as an expression <br> We would describe 9x+5=32 as an
AlekseyPX

Answer: Equation

Step-by-step explanation: because it has an equal sign. I think that’s what this question means.

6 0
3 years ago
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