Harry can first substitute 30 for t
He can then multiply
by 30 to get a product of 10
Since, 10 is not equal to 15, Harry's solution is not correct.
<em><u>Solution:</u></em>
Given that,
Harry solves the equation:
![\frac{1}{3}t = 15](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dt%20%3D%2015)
He says the solution is 30
We have to check if his answer is correct or not
<em><u>Fill in the blanks to explain how Harry can check whether his solution is correct</u></em>
Harry can first substitute 30 for t
![\frac{1}{3} \times 30 = 15](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%2030%20%3D%2015)
He can then multiply
by 30 to get a product of 10
![10\neq 15](https://tex.z-dn.net/?f=10%5Cneq%2015)
Since, 10 is not equal to 15, Harry's solution is not correct
<em><u>Correct solution:</u></em>
![\frac{1}{3}t = 15\\\\t = 15 \times 3\\\\t = 45](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dt%20%3D%2015%5C%5C%5C%5Ct%20%3D%2015%20%5Ctimes%203%5C%5C%5C%5Ct%20%3D%2045)
Thus correct solution is 45