<h3><u>Given</u><u>:</u><u>-</u></h3>
- Perimeter of parallelogram = 66 ft
<h3><u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u><u>-</u></h3>
Find the longest side of a parallelogram.
<h3><u>Formula</u><u> </u><u>used</u><u>:</u><u>-</u></h3>
Perimeter of parallelogram = 2 ( a + b )
<h3>
<u>Solution:-</u><u> </u></h3>
We know that,
Perimeter of parallelogram = 2 ( a + b )
★ Substituting the values in the above formula,we get:
⇒ 66 = 2 ( 3x + 1 + 2x - 3 )
⇒ 66 = 2 ( 5x - 2 )
⇒ 66/2 = 5x - 2
⇒ 33 = 5x - 2
⇒ 5x - 2 = 33
⇒ 5x = 33 + 2
⇒ 5x = 35
⇒ x = 35/5
⇒ x = 7 ft
Now,
One side,a = 3x + 1
★ Putting the value of x
⇒ 3 × 7 + 1
⇒ 21 + 1
⇒ 22 ft
Other side,b = 2x - 3
★ Putting the value of x
⇒ 2 × 7 - 3
⇒ 14 - 3
⇒ 11 ft
Hence,the longest Side of given parallelogram is 22 ft ( 3x + 1 ) .
Apply Pythagoras:
length = sqrt( (10--4)² + (6-3)² ) = sqrt(205)
Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
If you make them have the same denominator the fractions would be
12/15 - 5/15=
this equals 7/15 and you can't simplify it.
