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3 years ago

Write an example of an expression that cannot be simplified, and explain how you know that it cannot be simplified

Mathematics

1 answer:

Natali5045456 [20]3 years ago

8 0

Answer: -1+6y+7x

To simplify expressions, you have to be able to combine like terms (eg. 3x and 2x to get 5x). Since there are none in this expression, and you can't combine y and x, this expression can't be simplified.

*If it helps, think of x and y as different types of candy... ;3

For example, you can't combine 12 Skittles (x) and 4 Reese's (y), because they aren't the same. So, you'd write that you have 12 Skittles and 4 Reese's.

Hope this helps,

LaciaMelodii :)

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last week a candle store recieved 335.60 for selling 20 candles. small candles sell for 10.98 and largr candles sell fer 27.98.

mina [271]

Hmmmm closest I can get to this answer is 6 or 7. The numbers don't add up and it's probably why you haven't received an answer. If you do this math:
13small candles multiplied by 10.98 = 142.74
7large candles multiplied by 27.98 = 195.86
142.74+195.86 = 338.60 which is OVER the total received.
7+13=20 candles
14small candles multiplied by 10.98 = 153.72
6 large candles multiplied by 27.98 = 167.88
153.72+167.88 = 321.60 which is UNDER the total received
Can't go any lower or higher because it's even lower or higher.
6+14=20 candles
So I wouldn't really know what to say. This isn't adding up.

5 0

3 years ago

What is 22% of 50???????????

miss Akunina [59]

22% of 50 is 11.
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8 0

3 years ago

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Add (x^2 − 4x +5) + (7x^2 +2x− 3) help me

Ganezh [65]

This is a puzzling question, so my answer is not 100%, but:
"8 x^2 - 2 x + 2" is what I got.

4 0

3 years ago

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Circle 1, Circle 2, and Circle 3 have the same center and have radii, respectively, of r₁ cm, r₂ cm, r₃ cm, where r₁ < r₂ &lt

ira [324]

Answer:

a) A₁ /A₂ = r₁² / (r₂² - r₁²)

b) A₂ /A₃ = (r₂² - r₁²) / (r₃² - r₂²)

Step-by-step explanation:

We have Circle 1 and area A₁

Area of circle 2 outside circle 1 = A₂

Area of circle 3 outside circle 2 = A₃

On the other hand we have

A₁ = π*r₁² area of circle 1

A₂´ = π*r₂² area of circle 2

A₃´ = π*r₃² area of circle 3

All areas in cm²

a) A₁ /A₂

A₁ = π*r₁²

According to problem statement A₂ = π*r₂² - A₁

A₂ = π*r₂² - π*r₁² ⇒ A₂ = π* (r₂² - r₁²)

Then A₁ /A₂ = π*r₁² / [π* (r₂² - r₁²)]

A₁ /A₂ = r₁² / (r₂² - r₁²)

b) A₂ /A₃

A₂ = π* (r₂² - r₁²)

And

A₃ = π* (r₃² - r₂²)

Therefore

A₂ /A₃ = π* (r₂² - r₁²) / π* (r₃² - r₂²) ⇒ A₂ /A₃ = (r₂² - r₁²) / (r₃² - r₂²)

A₂ /A₃ = (r₂² - r₁²) / (r₃² - r₂²)

6 0

3 years ago

ΟΑ. -642 Ο Ο Β. 162 C. 1672 Ο Ο D. 642 O Ε. -162

hjlf

Answer: With the equation being negative you would multiply it to most likely get a positive if Z is Negative. If Z is a positive but also a higher number the equation is defenitly positive. I dont know the exact answer do to the fact that you didint show the whole question.

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3 years ago