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Lana71 [14]
3 years ago
8

Given the following system of equations, what value of x makes the equations true?

Mathematics
1 answer:
Marat540 [252]3 years ago
6 0
If you mean value of y, the value of y is 0.25. hope this helped
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What is the solution to the system of equation <br><br> -2x+6y=-38<br> 3x-4y=32
Alla [95]

Answer:

x= 4

y= -5

Step-by-step explanation:

-2x+6y=-38    equation 1

3x-4y=32     equation 2

using equation 1 we have:

-2x+6y=-38  

6y +38 = 2x

3y + 19 = x   equation 3

using equation 3 in equation 2 we have:

3(3y + 19) - 4y = 32

9y + 57 -4y =32

5y = 32 -57

5y = -25

y= -25/5

y = -5

so we have:

3y + 19 = x  

3(-5) +19 = x

x= 4

5 0
3 years ago
Read 2 more answers
Write 8.92x10^9 in standard notation.
Mandarinka [93]
8920000000.
Since the problem is asking for a positive 10^9 power, the final number with be greater than 8.92
7 0
3 years ago
Help me to solve problem pless​
sergejj [24]

Answer:

a:

5 x -3 +6

= 5 x 6 + -3

= 30 + -3

= 27

8 0
2 years ago
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Find the indicated arc and angle measures:
nevsk [136]

Answer:

arc AB = 70°

arc BC = 110°

arc ABC = 180°

arc CDB = 250°

Step-by-step explanation:

Since these angles are not inscribed, but are at the center point of the circle, the angles and arcs will be the same measure.

Solve for arc AB:

Angle AFB = 70°, so arc AB = 70°

Solve for arc BC:

Angle AFC is a straight angle so it is 180°. To find angle BFC, subtract angle AFB from 180°.

180 - 70 = 110°

Since angle BFC = 110°, arc BC = 110°

Solve for arc ABC:

Add arc AB and arc BC together.

70° + 110° = 180°

arc ABC = 180°

Solve for arc CDB:

There are 360° in a cirlce. To find arc CDB, subtract arc BC from 360°.

360° - 110° = 250°

arc CDB = 250°

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3 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. <br> IM GIVING 40 POINTS !! DONT SKIP :((.
fenix001 [56]

Answer:

m=1/3

b=5

y=1/3x+5

positive slope

8 0
3 years ago
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