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3 years ago

If the rates of change are variable, the equation is linear. True False

Mathematics

2 answers:

kirill [66]3 years ago

8 0

True is correct

brainliest? plz/thx or nope/not today

maria [59]3 years ago

4 0

The correct answer would be true! :)

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Justin used 42 centimeters of tape to wrap 14 presents. How many presents did Justin wrap if

Liono4ka [1.6K]

Answer:

15 presents

Step-by-step explanation:

42 cm / 14 presents = 3 cm / 1

3cm / 1 presents = 45 / 15

7 0

3 years ago

Read 2 more answers

Solve the inequality and express your answer in interval notation<br> x^2+8x+5 <0

irakobra [83]

The interval notation is $(-\sqrt{11}-4, \sqrt{11}-4)$

Explanation:

The inequality is $x^{2}+8 x+5$

Let us complete the square, we get,

$x^{2}+8 x+5+4^{2}-4^{2}$

Simplifying, we have,

$(x+4)^{2}+5-4^{2}$

$(x+4)^{2}-11$

Adding both sides of the equation by 11, we get,

$(x+4)^{2}$

Since, we know that for $u^{n}$ , if n is even then $-\sqrt[n]{a}$

Thus, writing the above expression in this form, we get,

$-\sqrt{11}$

Also, if $a$ then $a$ and $u$

Then ,we have,

$-\sqrt{11}$ and $x+4$

Solving the inequalities, we get,

$-\sqrt{11}\ \ \ \ \ \$ and $x+4$

Merging the intervals, we have,

$-\sqrt{11}-4$

Hence, writing the solution in interval notation, we have,

$(-\sqrt{11}-4, \sqrt{11}-4)$

Therefore, the answer is $(-\sqrt{11}-4, \sqrt{11}-4)$

7 0

3 years ago

The hopper bin in the picture below is modeled by the two-dimensional figure beside it. The hopper bin is

Zepler [3.9K]

The volume of the hopper bin is the amount of feed in it

The volume of the hopper bin is 35974 cubic feet
The carnival tent can be filled to 85% of its volume and not exceed the weight limit

<h3>The volume of the hopper bin</h3>

The given parameters are:

Height of cylinder, H = 20 ft
Diameter of cylinder, D = 36 feet
Angle, θ = 52°

Start by calculating the radius (r) of the cones.

r = D/2 -------- because the cones and the cylinder have equal diameters.

So, we have:

r = 36/2 = 18

The height (h) of the cones is:

tan(θ) = h/r

This gives

tan(52) = h/18

Make h the subject

h = 18 * tan(52)

Evaluate

h = 23.04

The volume is then calculated as:

Volume = Volume of cylinder + 2 * Volume of cone

This gives

Volume = πr^2H + 2 * 1/3πr^2h

Volume = πr^2H + 2/3πr^2h

Factor out πr^2

Volume = πr^2(H + 2/3h)

Substitute known values

Volume = 3.14 * 18^2 * (20 + 2/3 * 23.04)

Evaluate

Volume = 35973.85 cubic feet

Hence, the volume of the hopper bin is 35974 cubic feet

<h3>The weight limit of the hopper bin</h3>

The given parameters are:

Maximum weight = 500000 pounds
Feed weight = 22 pounds per cubic feet

For a feed that weighs 22 pounds per cubic feet, the weight of the hopper bin would be:

Weight = 22 * 35974 pounds

Weight = 791428 pounds

At 85% full, the weight wuld be:

Weight = 85% * 791428 pounds

Weight = 672713.8 pounds

672713.8 pounds is greater than the weight limit of 500000 pounds.

Hence, the carnival tent can be filled to 85% of its volume and not exceed the weight limit