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3 years ago

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At 1:30 marlon left his house to go to the beach a distance of 5.25 miles. He rode his skateboard until 2:15 and then walked the

rest of the way. He arrived at the beach at 3:00. Marlon's speed on his skateboard is 2.5 times his walking speed. Find his speed when skateboarding and when walking.

1 answer:

sergeinik [125]3 years ago

6 0

Answer: his speed when skateboarding 5 mph and when walking is 2 mph

Step-by-step explanation:

Marlon started riding his skateboard from his house at 1:30 until 2:15 when he started walking. This means that the time he spent riding his skateboard is

2:15 - 1:30 = 45 minutes

Converting 45 minutes to hours, it becomes

45/60 = 0.75 hour

He walked the rest of the way. He arrived at the beach at 3:00. This means that the time he spent walking is

3:00 - 2:15 = 45 minutes

Converting 45 minutes to hours, it becomes

45/60 = 0.75 hour

Let x represent Marlon's walking speed.

Marlon's speed on his skateboard is 2.5 times his walking speed. This means that his speed when skateboarding is 2.5x

Distance = speed × time

Distance covered while walking is

x × 0.75 = 0.75x

Distance covered while skateboarding is

2.5x × 0.75 = 1.875x

Since the total distance to the beach is 5.25 miles, then

0.75x + 1.875x = 5.25

2.625x = 5.25

x = 5.25/2.625

x = 2mph

His speed while skateboarding is

2.5x = 2.5 × 2 = 5mph

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lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

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Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

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$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

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