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3 years ago

What equation represents the line that passes through the points (-3 7 and (3 3?

1 answer:

3 0

Hello : let A(-3,7) B(3,3)
the slope is : (YB - YA)/(XB -XA)
(3-7)/(3+3) = -2/3
an equation is : y=ax+b a is a slope

y = (-2/3)x +b

the line through point B (3,3) : 3 = (-2/3)(3)+b
b =5
the equation is : y =(-2/3)x+5

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Prove that :- Cos3A-cosA/sin3A-sinA+cos2A-cos4A/sin4A-sin2A=sinA/cos2Acos3A

ad-work [718]

$\dfrac{\cos^3A-\cos A}{\sin^3A-\sin A}+\dfrac{\cos^2A-\cos^4A}{\sin^4A-\sin^2A}=\dfrac{\sin A}{\cos^2A\cos^3A}\\\\L_s=\dfrac{\cos A(\cos^2A-1)}{\sin A(\sin^2A-1)}+\dfrac{\cos^2A(1-\cos^2A)}{\sin^2A(\sin^2A-1)}\\\\=\dfrac{\cos A(-\sin^2A)}{\sin A(-\cos^2A)}+\dfrac{\cos^2A\sin^2A}{\sin^2A(-\cos^2A)}\\\\=\dfrac{\sin A}{\cos A}-1=\tan A-1$

$R_s=\dfrac{\sin A}{\cos A\cos^4A}=\dfrac{\sin A}{\cos A}\cdot\dfrac{1}{\cos^4A}=\tan A\cdot\dfrac{1}{\cos^4A}=\dfrac{\tan A}{\cos^4A}$

$\boxed{L_s\neq R_s}$

8 0

2 years ago

Write the equation of each line using the given information.

MrRissso [65]

Answer:

See explanation.

Step-by-step explanation:

We need a point and a slope to have a point slope equation.

$y-y_{1}=m(x-x_{1})$

We need a slope and y-intercept to write in slope intercept form.

$y=mx+b$

A) $y-1=\frac{1}{2}(x+4)$ or $y=\frac{1}{2}x+3$

B) $y+1=-1(x-2)$

C) $y-1=0(x-1)$

D) $y=-3x+8$

4 0

3 years ago

The interior angles formed by the sides of a pentagon have measures that sum to 540°. What is the measure of angle B?

patriot [66]

Answer:

m∠B = 110°

Step-by-step explanation:

We know that,

The sum of the measures of the angles in a pentagon is 540°.

So, we get,

130 + (x-5) + (x+30) + 75 + (x-35) = 540

i.e. 3x + (130+30+75) - (5+35) = 540

i.e. 3x + 235 - 40 = 540

i.e. 3x + 195 = 540

i.e. 3x = 540 - 195

i.e. 3x = 345

i.e. x= 115°

Now, as m∠B = (x-5)° = (115-5)° = 110°

Hence, the measure of angle B is 110°.

4 0

3 years ago

Read 2 more answers

Given g(x) = 2x + 1, solve for a when g(x) = 7.

Over [174]

You would evaluate by plugging in the given number of 7 to get your answer.

7 0

2 years ago

An arithmetic sequence is represented in the following table. Enter the missing term of the sequence.

bija089 [108]

$a_1=-9\\\\a_2=a_1-8\to a_2=-9-8=-17\\\\a_3=a_2-8\to a_3=-17-8=-25\\\\a_4=a_3-8\to a_4=-25-8=-33\\\\\text{The general term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\a_1-first\ term\\d-common\ difference\\\\\text{We have}\ a_1=-9\ \text{and}\ d=-8.\ \text{Substitute:}\\\\a_n=-9+(n-1)(-8)=-9-8n+8=-8n-1\\\\\text{Put n = 43 and calculate}\ a_{43}\\\\a_{43}=-8(43)-1=-344-1=-345\\\\Answer:\ \boxed{?=-345}$

4 0

3 years ago