All categories

3 years ago

Someone help me with this question ASAP please!!

Mathematics

1 answer:

Sever21 [200]3 years ago

4 0

Answer:

Step-by-step explanation:

Because 7000*1.09= 7630

and 5000*1.11= 5550 which are both equal to the amount each account will have after one year where they have gained interest.

In the first account 7630-7000=630 and the second 5550-5000=550

which is how much each gained in interest. together that makes 630+550=1180 in interest.

You might be interested in

1/3 + 1/2 + 1 2/3 - 4/5

mash [69]

17/10
or 1 7/10
i did it on my calculator lol

3 0

3 years ago

Question 5 (Multiple Choice Worth 4 points)

loris [4]

(-2,2) (0,1)
slope = y1-y2/x1-x2 .... 2-1/-2-0 = -1/2 the answer is C

7 0

3 years ago

Read 2 more answers

Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

The variance = 999,000

The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

= 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean = $\mu = \frac{1}{p}$

= $\mu = \frac{1}{0.001}$

= 1000

Variance = $\sigma ^2=\frac{1-p}{p^2}$

= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

= $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

= $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0

3 years ago

There were 200,000 animals of a certain species in 1980. Since then,this number has decreased by 4.5% each year. Approximately h

g100num [7]

Answer: Approximately 25187 animals of this species will be left in 2025

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

y = b(1 - r)^x

Where

y represents the population of animals after x years.

x represents the number of years.

b represents the initial population of animals.

r represents rate of decay.

From the information given,

b = 200000

r = 4.5% = 4.5/100 = 0.045

x = 2025 - 1980 = 45 years

Therefore,

y = 200000(1 - 0.045)^45

y = 200000(0.955)^45

y = 25187

8 0

3 years ago

Read 2 more answers

Suppose a + b = 0.

Digiron [165]

I'm pretty sure that it's b. That's assuming that you find the negative of b^2 and not the square of negative b.

5 0

3 years ago