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sukhopar [10]
3 years ago
15

How may cups are In a gallon

Mathematics
2 answers:
irinina [24]3 years ago
7 0

Answer:

I think it is 16 cups in a gallon

mars1129 [50]3 years ago
6 0
16US cups. I think that’s the right answer
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!!!!!!!please help!!!!!!!!
GuDViN [60]

Answer:

The first one is No. The second one I do not know unfortunately.

Step-by-step explanation:

I am in the middle of this lesson in my math class as well and I know that in order to make a triangle, you need the two smaller sides to add up to become larger than the biggest side. In the case of the first question, the two smaller sides, 6 and 3 equal 9, which is not bigger than the biggest side which is 10. I hope you can find the answer to the second one, but for now, the first one is No.

4 0
3 years ago
Helppppppppppppppppp pllllzzzzz<br> a<br> b<br> c
anastassius [24]
B I’m guessing, never really worked with something like this before though
3 0
3 years ago
Read 2 more answers
What is the amplitude, period, and phase shift of f(x) = -4 sin(2x + π) - 5?
son4ous [18]
F(x) = -4sin(2x + π) - 5

<u>Amplitude</u>
A = -π

<u>Period</u>
<u>2π</u> = <u>2π</u> = π
 B      2

<u>Phase Shift</u>
<u>-C</u> = <u>-π</u> = ≈ 1.57<u>
</u> B      2<u>
</u>
3 0
3 years ago
Read 2 more answers
Can someone help me out?
stira [4]

Answer:

  40 degrees

Step-by-step explanation:

A triangle solver tool can find the angle easily. It is 39.8°, which rounds to 40°. Apps are available on some calculators, on the Internet, and for iOS and Android phones and tablets.

___

You may be expected to solve this using the Law of Cosines. If we name the sides ...

  • a = 1.75
  • b = 3.00
  • c = 2.00

the law of cosines tells us the relationship is ...

  c² = a² + b² -2ab·cos(θ)

Then the angle is ...

  θ = arccos((a² +b² -c²)/(2ab)) = arccos((3.0625 +9 -4)/(2·1.75·3))

  = arccos(8.0625/10.5) ≈ 39.838° ≈ 40°

4 0
3 years ago
Which point satisfies the system of equations y = 3x − 2 and y = -2x + 3?
Sedbober [7]

Answer:

(1,1)

Step-by-step explanation:

The choices are not visible, however are unnecessary to solve this problem.

Given y = 3x - 2 and y = -2x + 3

[Set them equal to each other]

3x - 2 = -2x + 3

[Find x]

3x + 2x - 2 = 3

3x + 2x = 5

5x = 5

x = 1

[Plug x = 1 to both equations to check and find y]

y = 3x - 2

y = 3(1) - 2 = 3 - 2 = 1

y = -2x + 3

y = -2(1) + 3 = -2 + 3 = 1

Both are equal to y = 1 when x = 1

The point is then: (1,1)

3 0
3 years ago
Read 2 more answers
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