<span>All of the following are parts of the word processing window except for the button esc ____.</span>
Answer:
"Crowdsourcing" is the correct answer for the above question.
Explanation:
- Crowdsourcing is a term from which any organization advertises the thinks or can get the ideas or solutions for any particular problem.
- It is a term that refers to the problem to the number of solvers to achieve the result correct and frequent.
- For example, If anyone wants to prepare the two websites. Then he assigns the works to the number of people and the works done faster with the help of this.
- The above question states that some websites can be successful with the help of the type of work. They are successful with the help of crowdsourced work. Because it saves time. So the answer is Crowdsourcing.
A feature in Excel that allows you to graphically display in a single cell the trend across a range of cells is called a sparkline.
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
Answer:
Provide requested web pages to clients; the other tasks listed there are secondary to that.
