Answer:
Bobo Bunny is heterozygous for long legs. What is his genotype? Ll
Betty Bunny is also heterozygous for long legs. What is her genotype? Ll
Draw the Punnett Square and answer the question.
What are the possible genotypes, phenotypes and percentages of each for their babies?
Ll x Ll= LL, Ll, Ll, and Ll
All the offspring have long legs with one homozygous Long leg and three heterozygous long legs
Explanation:
Explanation:
- Dull fruit (D) is dominant over glossy (d) fruit.
- Orange friut (R) is dominant over cream fruit (r).
- Bitter cotyledon (B) is dominant over non-bitter cotyledons (b).
The three genes are independent.
<h3>a)</h3>
- A plant homozygous for dull, orange fruit and bitter cotyledons has the genotype <em>DDRRBB</em><em>.</em>
- A plant homozygous for glossy, cream fruit and non-bitter cotyledons has the genotype <em>ddrrbb</em>.
100% of the F1 will have dull, orange fruit and bitter cotyledons and will be heterozygous for all genes: <em>DdRrBb</em>.
<u>The F2 will have 8 possible phenotypes:</u>
- 27 D_R_B dull, orange fruit and bitter cotyledons
- 9 D_R_bb dull, orange fruit and non-bitter cotyledons
- 9 D_rrB_ dull, cream fruit and bitter cotyledons
- 3 D_rrbb dull, cream fruit and non-bitter cotyledons
- 9 ddR_B_ glossy, orange fruit and bitter cotyledons
- 3 ddR_bb glossy, orange fruit and non-bitter cotyledons
- 3 ddrrB_ glossy, cream fruit and bitter cotyledons
- 1 ddrrbb glossy, cream fruit and non-bitter cotyledons
<h3>b)</h3>
An F1 plant is crossed with a plant that has glossy, cream fruit and non-bitter cotyledons.
<h3>
DdRrBb x ddrrbb </h3>
The F1 individual can produce 8 types of gametes: DRB, DRb, DrB, Drb, dRB, dRb, drB and drb. The cream fruit and non-bitter cotyledons individual can only produce drb gametes. This cross also produces a progeny with the following genotypes and phenotypic proportions:
- 8 DdRrBb dull, orange fruit and bitter cotyledons
- 8 DdRrbb dull, orange fruit and non-bitter cotyledons
- 8 DdrrBb dull, cream fruit and bitter cotyledons
- 8 Ddrrbb dull, cream fruit and non-bitter cotyledons
- 8 ddRrBb glossy, orange fruit and bitter cotyledons
- 8 ddRrbb glossy, orange fruit and non-bitter cotyledons
- 8 ddrrBb glossy, cream fruit and bitter cotyledons
- 8 ddrrbb glossy, cream fruit and non-bitter cotyledons
Answer:
Explanation:
The photosynthesis equation is as follows: 6CO2 + 6H20 + (energy) → C6H12O6 + 6O2 Carbon dioxide + water + energy from light produces glucose and oxygen.
Answer:
All living organisms respire. Cells need and use the energy that is formed through this process to assist with life processes in order for organisms to survive and reproduce. Oxygen and carbon dioxide are the main gases involved in aerobic respiration. These conditions are called gas exchange surfaces.
Explanation:
Answer:
D. Sulfur
Explanation:
Electrons are filled in shells. Oxygen has a total of 8 electrons while sulfur has a total of 16 electrons. Out of the total eight electrons, the first shell has two electrons while six electrons are filled in the “s and p” orbits of the second shell giving the outer shell a configuration of "2s2, 2p4".
Likewise, out of the total 16 electrons of sulfur, the last 6 electrons are filled in "s" and "p" orbits of the third shell. Sulfur has a total of six electrons in its outer most shell "3s² 3p⁴". Since the electrons present in the outer most shell are available for chemical reactions and determine the chemical nature of the atom, oxygen and sulfur should exhibit the same chemical properties.