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guapka [62]
2 years ago
11

At the zoo there were 3 times as many monkeys as lions how many monkey were there

Mathematics
1 answer:
Radda [10]2 years ago
7 0
Does it say how many lions there are?
Take the amount of lions and times it by three.
So 3x (X being the amount of lions).
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2 pounds of grapes cost $8 How do they cost per pound? How many pounds of grapes do you get per dollar?
stiks02 [169]

Answer:

$4 per pound and 0.25 pounds per dollar

Step-by-step explanation:

48 divided by 2 = $4

1 divided by 4 = 0.25

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What is the measure of ZP, to the<br> nearest degree?<br> O 44°<br> O 46°<br> 0 58°<br> 0 72°
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44

Step-by-step explanation:

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2 years ago
According to a​ survey, 60 ​% of the residents of a city oppose a downtown casino. Of these 60 ​% about 8 out of 10 strongly opp
katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

Step-by-step explanation:

​(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino. ​

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

  • Probability that a radomly selected resident opposes the casino: P(A)

  • Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the <em>probability that a radomly selected resident opposes the casino</em>, P(A)

Probability = number of favorable outcomes / number of possible outcomes

  • P(A) is <em>given as 60%</em>, which in decimal form is 0.60

ii) Next, determine,the <em>probability that a resident who opposes the casino strongly opposes it</em>, P(B/A):

  • It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or  intersection: P(A∩B).

So, you can use the definition of conditional probability:

  • P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

  • P(A∩B) = P(B/A)×P(A) =  (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that <em>a radomly selected resident who opposes the casino does strongly oppose the casino</em>, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

​(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the​ casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

8 0
3 years ago
I need help on everything on 45 45 90 right triangles. I dont know how to solve two variables when one is shown.
Ulleksa [173]
You can use a square plus b square equal C square to fijd each length . or you can memorize the special triangles or you can also do proportional problem. it all works
4 0
3 years ago
Help meeee please!!!!!
ladessa [460]

Answer:

Step 3: Choice D

Step 5: Choice B

Step 6: Choice A

Step 8: Choice C

(I saw in the top left corner of the picture that this is for Algebra II. I am in 8th grade, currently taking geometry, and I haven't taken Algebra II yet, but I <em>did</em> take Algebra I last year. I am 95% sure this is correct but if it isn't, the I sincerely apologize.)

7 0
3 years ago
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