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docker41 [41]
3 years ago
5

Parts of New Orleans is currently below sea level and continues to sink each year. NASA images shows that one part of the city i

s currently 6 feet(72 inches) below sea level. Each year it continues to sink 2 more inches. Write an expression to describe the depth of New Orleans after any given year.
Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0

Step-by-step explanation:

The Mathematical expression would be given as:

- (70 + 2n)

Where n represents any given year.

Negative sign is taken as it symbolises depth below sea level.

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Sara is a big hip-hop music fan. Her friend Matt is a big rap music fan. They each have a huge library of songs in their digital
Orlov [11]

The critical value is 1.99 and the null hypotheses is μ - μ₂ = 0 and alternative hypotheses for this test is μ - μ₂ ≠ 0.

According to the statement

we have given that the sample of songs is 50. and the average of hip hop is μ₂.

For this purpose, we know that the

Sara and matt would like to know if the average length of the hip hop songs say μ₁ differ from the average of the hip hop songs say μ₂. It means μ₁ ≠ μ₂.

so, The null and alternative hypothesis value are:

H(null) = μ - μ₂ = 0 And

H (alternative) = μ - μ₂ ≠ 0.

From this it is clear that the this the value of hypothesis.

So,

Now, Let the degree of freedom be a x.

Then

At \alpha = 0.05 then the value of k is 80,.

Then the critical value is

t = (\frac{\alpha }{2} , k) = 1.99

Here the critical vale is 1.99.

So, The critical value is 1.99 and the null hypotheses is μ - μ₂ = 0 and alternative hypotheses for this test is μ - μ₂ ≠ 0.

Learn more about null and alternative hypothesis here

brainly.com/question/15980493

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Sara is a big hip-hop music fan. Her friend Matt is a big rap music fan. They each have a huge library of songs in their digital music libraries. They each randomly sample 50 songs from their libraries and record the lengths of the songs selected. The average of the selected hip hop songs was *, - 245 seconds with a sample standard deviation of 5 seconds. The average of the selected rap songs was X - 275 seconds with a sample standard deviation of 6 seconds. They would like to know if the average length of hip-hop songs is different than the average length of rap songs. (a) What are the appropriate null and alternative hypotheses for this test? (b) Assume for purposes of this study, the degrees of freedom are 80. At a 5% significance level, what is the critical value for the test?

#SPJ4

8 0
2 years ago
A worker at a snack stand opened a new box of cups. The first day, the worker used
Alex_Xolod [135]
A:400 cups in the box
7 0
3 years ago
HELPPPP!!!! <br> Need the answer ASAP!!
Greeley [361]

<u>Given </u>that the functions f(x)=x+4 and g(x)=x^{3}

We need to determine the value of the function (g \ {\circ} f)(-3)

First, we shall determine the composition of the function (g \circ f)(x)

<u>Function </u>(g \circ f)(x)<u>:</u>

Let us determine the function (g \circ f)(x)

Thus, we have;

(g \circ f)(x)=g[f(x)]

               =g[x+4]

               =(x+4)^3

(g \circ f)(x)=x^3+3x^2(4)+3x(4)^2+(4)^3

(g \circ f)(x)=x^3+12x^2+48x+64

Thus, the function is (g \circ f)(x)=x^3+12x^2+48x+64

<u>Value of the function </u>(g \ {\circ} f)(-3)<u>:</u>

The value of the function can be determined by substituting x = -3 in the function (g \circ f)(x)=x^3+12x^2+48x+64

Thus, we have;

(g \circ f)(-3)=(-3)^3+12(-3)^2+48(-3)+64

Simplifying the terms, we get;

(g \circ f)(-3)=-27+12(9)+48(-3)+64

(g \circ f)(-3)=-27+108-144+64

(g \circ f)(-3)=1

Thus, the value of the function (g \ {\circ} f)(-3) is 1.

8 0
3 years ago
Which of the points is not a solution to 3x+2y=11
allochka39001 [22]
Answer : Option B

------------------------------
when x = -3 , check for y
------------------------------
3(-3) + 2y = 11
-9 + 2y = 11
2y = 11+9 
2y = 20
y = 10
The coordinate is (-3, 10)
4 0
3 years ago
Need help please help me
choli [55]
It should be the second one
4 0
3 years ago
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