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vaieri [72.5K]
4 years ago
14

Which angle in triangle ABC has the smallest measure?​

Mathematics
1 answer:
ludmilkaskok [199]4 years ago
4 0

Answer:

Angle B

Step-by-step explanation:

To find the smallest angle it is the opposite of the smallest side in the triangle in this case as all sides are given.

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I need help please.
kow [346]

Answer:

(2,1)

Step-by-step explanation:

the order of pair is 2,1

8 0
3 years ago
Read 2 more answers
PLEASE HELPPPPPPPPPPPPPP THANK YOUUH
almond37 [142]
For A B and C, you just plug in the given number

A
2(15) + 5 = 35
B
4(20) + 2 = 82
C
6(10) + 5 = 65
And for D, you set the equation to 26 and solve for n
3x + 5 = 26 \\ 3x = 21 \\ x = 7
I had to use x instead of n, but for D n=7. :)

8 0
4 years ago
Add the two expressions.<br><br> 2x + 6 and 6x −1<br><br> Enter your answer in the box.
MA_775_DIABLO [31]

Answer:

8x +5

Step-by-step explanation:

The sum is found by combining "like" terms—those that have the same arrangement of variables.

The first expression, 2x +6, has terms 2x and 6.

The second expression, 6x -1, has terms 6x and -1.

In each case, the first term listed is first-degree in the variable x. These are "like" terms, so can be added:

... 2x +6x = (2+6)x = 8x

The second term listed in each case is a constant. These are "like" terms, so can be added:

... 6 + (-1) = 5

Then the sum of the given expressions is the sum of the results from adding like terms:

... 8x + 5

4 0
3 years ago
Please help me with this and find x!! Thank you, only if you know!
scoray [572]

Answer:

x = 9.8

Step-by-step explanation:

to find x, use pythagorean theorem

a^{2} = c^{2} - b^{2}

a^{2} = 14^{2}  - 10^{2}

a^{2} = 196 - 100

a^{2} = 96

\sqrt{a^2} = \sqrt{96}

a = 9.7979 ⇒ 9.8

7 0
3 years ago
Read 2 more answers
Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the
BigorU [14]

The average travel time is simply the mean travel time between the given points

  • The average time that it takes for the car to travel the first 0.25m is 2.23s.
  • The average time to travel just between 0.25m and 0.50m is 0.9s.
  • Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

<u>(a) The average time to travel the first 0.25m</u>

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

Time = \frac{2.24s + 2.21s + 2.23s}{3}

Time = \frac{6.68s}{3}

Time = 2.23s

<u>(b) The average time to travel just between 0.25m and 0.50m</u>

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

Time = \frac{3.16s + 3.08s + 3.15s}{3}

Time = \frac{9.39s}{3}

Time = 3.13s

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

Average = 3.13s - 2.23s

Average = 0.9s

<u>(c) The velocity in the second 0.25m section</u>

The distance and time are:

Distance = 0.25m

Time = 0.9s

So, the velocity is:

Velocity = \frac{Distance}{Time}

This gives

Velocity = \frac{0.25m}{0.9s}

Velocity = 0.28m/s

Read more about distance, velocity and time at:

brainly.com/question/4931057

6 0
3 years ago
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