15) 4m^2
17)9n^6
198a^2 (^ = power of)
Answer:
The degrees of freedom are given by:
![df = n-1=14-1=13](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D14-1%3D13)
The significance level is
and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:
![\chi^2_{\alpha}= 22.362](https://tex.z-dn.net/?f=%20%5Cchi%5E2_%7B%5Calpha%7D%3D%2022.362)
And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.
Step-by-step explanation:
We have the followign system of hypothesis:
Null hypothesis: ![\sigma^2 \leq 3.5](https://tex.z-dn.net/?f=%5Csigma%5E2%20%5Cleq%203.5)
Alternative hypothesis: ![\sigma^2 >3.5](https://tex.z-dn.net/?f=%20%5Csigma%5E2%20%3E3.5)
The degrees of freedom are given by:
![df = n-1=14-1=13](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D14-1%3D13)
The significance level is
and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:
![\chi^2_{\alpha}= 22.362](https://tex.z-dn.net/?f=%20%5Cchi%5E2_%7B%5Calpha%7D%3D%2022.362)
And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.
Answer:
Speed = Distance ÷ Time
time = distance ÷ speed
Step-by-step explanation:
248 ÷ 55 * 60 = 270.54 minutes