Explanation:
It is given that a particle covers 10m in first 5s and 10m in next 3s. so using the equation of motion
Case I
s=ut+
2
1
at
2
10=5u+
2
1
a(5)
2
20=10u+25a
4=2u+5a..............(1)
Case 2
In next 3s the particle covers more 10m distance. So
20=8u+
2
1
a(8)
2
5=2u+8a.........(2)
On solving equation (1) and (2)
4=2u+5a
5=2u+8a
a=
3
1
m/s
2
Put the value of a in equation (1)
u=
6
7
m/s
Now to find distance in next 10 s. total time will be 10s
s=
6
7
×10+
2
1
×
3
1
×(10)
2
s=28.33m
Distance travelled in next 2 sec
s=28.33−20=8.33m
Answer:
If the thrust is increased, the aircraft accelerates and the velocity increases. This is the second part sited in Newton's first law; a net external force changes the velocity of the object. The drag of the aircraft depends on the square of the velocity. So the drag increases with increased velocity.
Answer:
2123.55 $/hr
Explanation:
Given parameters are:
KV
L = 143 km
I = 500 A
So, we will find the voltage potential provided for the city as:
kV
kV
Then, we will find dissipated power because of the resistive loss on the transmission line as:
W
Since the charge of plant is not given for electric energy, let's assume it randomly as 
Then, we will find the price of energy transmitted to the city as:
$/hr
To calculate money per hour saved by increasing the electric potential of the power plant:
Finally,
$/hr
The amount of money saved per hour = 
$/hr
Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.
You would want to include qualitative and quantitative evidence
The 'North pole' of any magnet is the one that would be attracted to the Earth's North magnetic pole. In that sense, they are just labels that identify the opposite magnetic force produced at each end of the magnet. The Earth'smagnetic field also has poles, North and South. more at study.com
