A particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity
2 answers:
Answer:
vi =2
Explanation:
Δx = 1/2 (vi + vf) t
10 = 1/2 ( vi + 8 ) 2
10 = vi + 8
10-8 = vi
vi = 2 m/s
vi= initial velocity
vf= final velocity
Δx= distance
t= time
Explanation:
It is given that a particle covers 10m in first 5s and 10m in next 3s. so using the equation of motion
Case I
s=ut+
2
1
at
2
10=5u+
2
1
a(5)
2
20=10u+25a
4=2u+5a..............(1)
Case 2
In next 3s the particle covers more 10m distance. So
20=8u+
2
1
a(8)
2
5=2u+8a.........(2)
On solving equation (1) and (2)
4=2u+5a
5=2u+8a
a=
3
1
m/s
2
Put the value of a in equation (1)
u=
6
7
m/s
Now to find distance in next 10 s. total time will be 10s
s=
6
7
×10+
2
1
×
3
1
×(10)
2
s=28.33m
Distance travelled in next 2 sec
s=28.33−20=8.33m
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