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3 years ago

A particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity

Physics

2 answers:

EastWind [94]3 years ago

5 0

Answer:

vi =2

Explanation:

Δx = 1/2 (vi + vf) t

10 = 1/2 ( vi + 8 ) 2

10 = vi + 8

10-8 = vi

vi = 2 m/s

vi= initial velocity

vf= final velocity

Δx= distance

t= time

klasskru [66]3 years ago

4 0

Explanation:

It is given that a particle covers 10m in first 5s and 10m in next 3s. so using the equation of motion

Case I

s=ut+

10=5u+

a(5)

20=10u+25a

4=2u+5a..............(1)

Case 2

In next 3s the particle covers more 10m distance. So

20=8u+

a(8)

5=2u+8a.........(2)

On solving equation (1) and (2)

4=2u+5a

5=2u+8a

m/s

Put the value of a in equation (1)

m/s

Now to find distance in next 10 s. total time will be 10s

×10+

×(10)

s=28.33m

Distance travelled in next 2 sec

s=28.33−20=8.33m

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A particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity​

A particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity