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Ugo [173]
3 years ago
14

. Question: 23 of 24:. Which statement is true regarding DC current?. Select one of the options below as your answer:. . A.. The

electrons move back and forth.. B.. There can only be one voltage supplied.. C.. A high voltage current can be transformed into a low voltage current.. D.. A low voltage current can be transformed into a high voltage current.. E.. This is what is sent from the power plants to your home..
Physics
2 answers:
ikadub [295]3 years ago
6 0

Answer: The correct answer is B.

Explanation:

In DC current, the electric current flows only in one direction. The rate of flow of electrons constitutes the current.

DC voltage and DC current are constant with time.

For example, battery supplies DC voltage.

In AC current, the electric current reverses its direction periodically. Here, the electrons move back and forth. AC voltage can be supplied long distances. For example, AC voltage is supplied to our home.

Step-up and step-down transformers are used to increase or decrease the voltage.

The statement is true about DC current from the given options

is "There can only be one voltage supplied".

Umnica [9.8K]3 years ago
4 0
"<span>There can only be one voltage supplied" is the statement among the statements given in the question that true regarding DC current. The correct option among all the options that are given in the question is the second option or option "B'. I hope the answer comes to your help.</span>
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Answer:

The net force on the electron is given as:

F = 1.35 x 10⁻¹³ N j - 1.35 x 10⁻¹³ N i

Explanation:

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charge on rod along x-axis = Q₁ = -15 x 10⁻⁶ C

charge on rod along y-axis = Q₂ = 15 x 10⁻⁶ C

distance of electron from rod 1 = r₁ = 0.4 m

distance of electron from rod 1 = r₂ = 0.4 m

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ε° = 8.85 x 10⁻¹² C²/Nm²

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F₁ = qE = 1/4πε°(qQ₁/r₁²)

F₁ = (9 x 10⁹ x -1.6 x 10⁻¹⁹ x -15 x 10⁻⁶)/0.4²

F₁ = 1.35 x 10⁻¹³ N

Negative negative repels each other so the rod will Force the electron in positive y-direction.

F₁ = 1.35 x 10⁻¹³ N j

Electric force on charge due to rod 2:

F₂ = qE = 1/4πε°(qQ₂/r₂²)

F₂ = (9 x 10⁹ x -1.6 x 10⁻¹⁹ x 15 x 10⁻⁶)/0.4²

F₂ = - 1.35 x 10⁻¹³ N

Opposite charges attract each other so the rod will force the electron in negative x-direction.

F₂ =  - 1.35 x 10⁻¹³ N i

Net Force:

F = F₁ + F₂

F = 1.35 x 10⁻¹³ N j - 1.35 x 10⁻¹³ N i

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3 years ago
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