The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.
<h3>How to calculate the radius?</h3>From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.
Let A = area of the triangle
Let S = semi perimeter of the triangle.
The radius will be: = A/S
where,
The radius will be:
= 3.33cm
In conclusion, the radius is 3.33cm.
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Answer:
x = - , x =
Step-by-step explanation:
to find the points of intersection equate the 2 equations , that is
7x - 15 = 10 + 12x - 6x² ( subtract 10 + 12x - 6x² from both sides )
6x² - 5x - 25 = 0 ← factor the quadratic on left side
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 6 × - 25 = - 150 and sum = - 5
the factors are - 15 and + 10
use these factors to split the x- term
6x² - 15x + 10x - 25 = 0 ( factor the first/second and third/fourth terms )
3x(2x - 5) + 5(2x - 5) = 0 ← factor out (2x - 5) from each term
(2x - 5)(3x + 5) = 0
equate each factor to zero and solve for x
3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = -
2x - 5 = 0 ⇒ 2x = 5 ⇒ x =