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ELEN [110]
2 years ago
13

Which of these expressions is equivalent to (12^8)

Mathematics
1 answer:
omeli [17]2 years ago
6 0

Answer:

whart are the options

Step-by-step explanation:

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In an isosceles triangle the length of the base is 10 cm
lawyer [7]

The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.

<h3>How to calculate the radius?</h3>

From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.

Let A = area of the triangle

Let S = semi perimeter of the triangle.

The radius will be: = A/S

where,

S = \dfrac{(a + b + c)}{2} = \dfrac{(13 + 13 + 10)}{2} = 18

The radius will be:

 =\dfrac{(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{10})} { 18}

= 3.33cm

In conclusion, the radius is 3.33cm.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ4

5 0
2 years ago
PLEASE HELP! WILL MARK BRAINLIEST!!!
Reptile [31]

Answer: options two and three

Step-by-step explanation: have a great day!

6 0
3 years ago
Read 2 more answers
Center: (9,0), Radius: 5√3
densk [106]

Answer:

ากทก่หวไใหท่ปาก

Step-by-step explanation:

่ก่หาห่กาไย

7 0
3 years ago
Solve for the given length. The length of a rectangle is 3m longer than its width. The area of the rectangle is 154^2. What is t
Andre45 [30]
If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
7 0
2 years ago
Read 2 more answers
Could someone help me for this?
lina2011 [118]

Answer:

x = - \frac{5}{3} , x = \frac{5}{2}

Step-by-step explanation:

to find the points of intersection equate the 2 equations , that is

7x - 15 = 10 + 12x - 6x² ( subtract 10 + 12x - 6x² from both sides )

6x² - 5x - 25 = 0 ← factor the quadratic on left side

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 6 × - 25 = - 150 and sum = - 5

the factors are - 15 and + 10

use these factors to split the x- term

6x² - 15x + 10x - 25 = 0 ( factor the first/second and third/fourth terms )

3x(2x - 5) + 5(2x - 5) = 0 ← factor out (2x - 5) from each term

(2x - 5)(3x + 5) = 0

equate each factor to zero and solve for x

3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = - \frac{5}{3}

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = \frac{5}{2}

3 0
1 year ago
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