Answer:
D. 8 times
Step-by-step explanation:
lmk if its right bc im not too confident </33
Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Times both sides by 10
(10g)/10=-9*10
(10/10)g=-90
1g=-90
g=-90
Answer:
-4-5-6-7-8
Step-by-step explanation:
