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kicyunya [14]
2 years ago
10

A scale drawing uses the scale 3 in. = 20 ft. Find the missing measure. 57 in. = ____ ft

Mathematics
1 answer:
liberstina [14]2 years ago
6 0
380 feet would be your answer
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Using the data shown on the graph, which statements are correct
Tomtit [17]

Answer:

B, C, and E

Step-by-step explanation:

Let's consider each option given the graph shown above:

A. The ratio of x/y can be found using any point on the line, say, (5, 6). Thus, ratio of x/y = 5/6, not 6/5.

Option A is not correct.

B. If you check for y/x for any given point along the line, we would have the same result. So the ratio of y/x is consistent. Option B is correct.

C. The graph has a line that runs through the point of origin, so therefore, it represents a proportional relationship.

Option C is correct

D. If option C is correct, then option D is not correct.

E. If option C is correct, then option E is correct.

8 0
2 years ago
Round 2481.65 to the neartheast 10 tenth
gregori [183]

2481.7

         ^ is the tenth place.

The 5 would either round it up or down by one-tenth. Since we like big numbers... we'll round it to 7 from 6.

5 0
2 years ago
Read 2 more answers
What’s the value of positive l5l ?
Lelechka [254]

Answer:

5

Step-by-step explanation:

Absolute value |x| makes any number positive.

|5| = 5

5 0
2 years ago
One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
2 years ago
What is the vertical asymptote of this function?
liraira [26]

Answer:

D

Step-by-step explanation:

If y = log x is the basic function, let's see the transformation rule(s):

Then,

1. y = log (x-a) is the original shifted a units to the right.

2. y = log x + b is the original shifted b units up

Hence, from the equation, we can say that this graph is:

** 2 units shifted right (with respect to original), and

** 10 units shifted up (with respect to original)

<u><em>only, left or right shift affects vertical asymptotes.</em></u>

Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.

Answer choice D is right.

7 0
3 years ago
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