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2 years ago

Solve : t+2t squared

Mathematics

1 answer:

zloy xaker [14]2 years ago

3 0

Answer:

t=0 or t=-1/2

Step-by-step explanation:

Solve for t over the real numbers:

t (2 t + 1) = 0

Split into two equations:

t = 0 or 2 t + 1 = 0

Subtract 1 from both sides:

t = 0 or 2 t = -1

Divide both sides by 2:

Answer: |

| t = 0 or t = -1/2

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Find the missing angle<br> measures marked with<br> question marks.

slavikrds [6]

Answer:

First one- The ? across from 70 degrees is 70 degrees, and the ones on the side are both 110 degrees.

The second one- The one across 53 degrees is 53 degrees and the ones are the side are both 127 degrees.

Step-by-step explanation:

Take the shown angle and subract that by 180 degrees to get your answer for the missing angles. And the one across from the shown angle is the same number.

Hope this helped im not sure if its right though.

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3 years ago

Explain the steps you could use to solve 3y+6=30 for y <br> please someone help me

Lady bird [3.3K]

Is this quadratic equations

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2 years ago

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The heights of american men aged 18 to 24 are approximately normally distributed with a mean of 68 inches and standard deviation

Rudik [331]

A normal distribution is symmetrical about the mean. Therefore half of all young men are shorter than 68 inches.

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3 years ago

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

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3 years ago

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Bryan, Angela, Elan, and Fiona folded some paper flowers for their school fund-raising project. Elan folded one-fifth of the pap

Tamiku [17]

Answer:

a) 88

b) 162 $

Step-by-step explanation:

Given Bryan sold 9 more flowers than Elan

1/4 x - 1/5 x = 9

x/20 = 9

x = 180

Flowers with Bryan = 45

Flowers with Elan = 36

45+36 = 81

Remaining flowers = 99

Flowers with Fiona = 8/9 * 99 = 88

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3 years ago