What is the median of this set of data? 100, 102, 103, 106, 109
2 answers:
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First, let's find all the factors of 81:
81/3=27
27/3=9
9/3=3
3/1=1
So the factors of 81 are 3,3,3,3, (the numbers by which we divided here).
This means we can write down 81 as 3*3*3*3 or
- which is the answer to the question! (three to the power of 4)
81/3=27
27/3=9
9/3=3
3/1=1
So the factors of 81 are 3,3,3,3, (the numbers by which we divided here).
This means we can write down 81 as 3*3*3*3 or