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frez [133]
2 years ago
6

HELP PLEASE- i attached the pic

Mathematics
2 answers:
Lerok [7]2 years ago
4 0
I think it is distributive property maybe i’m not too sure
baherus [9]2 years ago
4 0


Step-by-step explanation:

ℎ 8 2 16 ℎ . 81 8 16-8 ℎ ℎ “ “

-
You might be interested in
Explain the steps involved in adding two rational<br> expressions.<br> DONE
Helen [10]

Answer

Step-by-step explanation: example

5/(X+2). + 2/(X+1)

Common denominator. Is both (X+2)(X+1)

So the first fraction needs (X+1) since it already has (X+2) the second fraction needs ( X+2)

5(X+1). / (X+2)((X+1) +. 2/(X+2)/(X+1)

So multiply 5 with X then 5 with 1 and 2 times X and 2 times 2

5x+5 + 2x+4 / (X+2)((X+1)

Answer 7x+9/ (X+2)(X+1)

8 0
3 years ago
??????????????????????
ale4655 [162]

Answer:

Area = 58 \ units^2

Step-by-step explanation:

We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:

a^2+b^2=c^2

In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:

3^2+7^2=c^2

9+49=c^2

c^2=58

c=\sqrt{58}

Since the area of a square is the side length square then...

Area =( \sqrt{58} )^2

The square root and the squared cancel out giving us...

Area = 58 \ units^2

3 0
3 years ago
#3 and 5 please<br> I don’t understand how to get them
denpristay [2]

Answer:

im bad with this kinda thing, just guess and start praying, goodluck

Step-by-step explanation:

6 0
2 years ago
Your 3 nieces and 3 nephews (6 children total) are visiting for the holidays. You must give them each a present. They all love l
marusya05 [52]

Answer:

The 6 Lego kits can be selected from the 9 available Lego kits in 84 ways.

Step-by-step explanation:

Use combinations to solve this problem.

Combination is defined as the selection of <em>r</em> elements from <em>n</em> distinct objects irrespective of the order. The objects cannot be replaced.

There are 9 Lego kits available.

And the total number of children is 6.

That is, we need to select 6 Lego kits from the 9 available Lego kits.

6 Lego kits can be selected from the 9 available Lego kits in 9\choose 6 ways.

Solving the combination as follows:

{9\choose 6}=\frac{9!}{6!\times(9-6)!} \\=\frac{362880}{720\times6}\\ =84

Thus, there are 84 ways to select 6 Lego kits from 9 available Lego kits.

4 0
3 years ago
Find five consecutive integers such that: "the sum of the first and 4 times the third is equal to 60 less than 3 times the sum o
Monica [59]

Consecutive integers are integers that come one after another in order. For example, 2, 3, and 4 are all consecutive integers, as well as 100, 101, and 102. In general, if we have some integer n, the consecutive integers following it will be n + 1, n + 2, n + 3, etc. Here, we have five. If we

  • Call the first integer n,
  • Then the second integer will be n + 1,
  • The third will be n + 2,
  • The fourth will be n + 3,
  • And the fifth will be n + 4.

Now, let's break down the equation in English. We'll use #1, #2, #3, #4, and #5 as stand-ins for the five integers just so we can get things set up, then we'll replace them with the expressions we came up with in the first part. Starting from the beginning of the statement, let's translate words to symbols:

  • "The sum of the first and 4 times the third" → #1 + 4 × #3
  • "is equal to" → = (maybe obvious, but still!)
  • "60 less than 3 times the sum of the second, fourth, and fifth" → 3 × (#2 + #4 + #5) - 60

Putting that all together, we get the equation

#1 + 4 × #3 = 3 × (#2 + #4 + #5) - 60.

Replacing our stand-ins for the expressions we came up with, it becomes

n + 4(n + 2) = 3[(n + 1) + (n + 3) + (n + 4)] - 60

We can now start to simplify our equation to find n (the first integer) and the rest will follow easily from that. I'll start by focusing on the left side. We can distribute and combine like terms like so:

n + 4(n+2) = n + 4n + 8 = 5n + 8

Dealing with the right, we can get rid of some redundant parentheses and carry out the same process:

3[(n + 1) + (n + 3) + (n + 4)] - 60 = 3(n + 1 + n + 3 + n + 4) - 60

= 3(3n + 8) - 60 = 9n + 24 - 60 = 9n - 36

Our simplified equation now becomes

5n + 8 = 9n - 36.

Subtracting 5n from either side:

8 = 4n - 36

Adding 36 to either side:

44 = 4n

And dividing either side by 4:

11 = n.

We now know that our first integer is 11, which means that our 5 consecutive integers are 11, 12, 13, 14, and 15.

7 0
3 years ago
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