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Novay_Z [31]
3 years ago
13

the square root of an integer n is between 6 and 7. write an inequality that expresses all the possible values for n

Mathematics
1 answer:
irina [24]3 years ago
5 0
6\ \textless \ \sqrt{x}\ \textless \ 7\\6^2\ \textless \ \sqrt{x}^2\ \textless \ 7^2\\36\ \textless \ x\ \textless \ 49
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Suppose that the only information we have about a function is that f (1) = 5 and the graph of its derivative is as shown.
Shtirlitz [24]
Please provide graph of derivative.
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Can someone help me on this I’m struggling to figure it out...
VikaD [51]

Answer:

It's D

Step-by-step explanation:

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3 years ago
PLEASE HELP! I WILL MARK BRAINLY!!
enyata [817]

Answer: D

Step-by-step explanation: Using pemdas parentheses is always first so the answer is D.

4 0
3 years ago
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Find the area of the region under the graph of f on [a, b].<br> f(x) = x2 − 8x + 17; [−1, 2]
Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

A = \int\limits^a_b {f(x)} \, dx

Applying to this question:

A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx

Then

F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x

A = F(2) - F(-1)

F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}

F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}

A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42

The area is 42 area units.

5 0
3 years ago
BC -<br> Round your answer to the nearest hundredth.<br> B<br> ?<br> 35<br> A<br> с<br> 2.
mario62 [17]

Answer:

BC ≈ 1.40

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

<u>Step 1: Identify</u>

Angle θ = 35°

Opposite Leg BC = <em>x</em>

Adjacent Leg AC = 2

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [Tangent]:                    tan35° = x/2
  2. Isolate <em>x</em>:                                        2tan35° = x
  3. Rewrite:                                          x = 2tan35°
  4. Evaluate:                                        x = 1.40042
  5. Round:                                            x ≈ 1.40
4 0
3 years ago
Read 2 more answers
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