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Verizon [17]
3 years ago
10

What would happen if hydrogen bonds form between any two nitrogenous bases in dna

Biology
1 answer:
ella [17]3 years ago
4 0
I believe that identical copies of original DNA wouldn't be formed. 
DNA has a strict pairing rule, adenine can only go with thymine, and cytosine can only go with guanine. 
This is because of thymine and adenine make 2 hydrogen bonds between each other, while cytosine and guanine form 3. Therefore bonding out of this order is impossible (unless it's a mutation in which there are exceptions). 
<span>When DNA replicates, each strand of the original DNA serves as a template for the new strand of DNA. Hence the new strand that goes with the first original DNA strand is the same as the second DNA strand. 
</span>If the bonding between the nitrogen bases is messed up, the new strand of DNA will not be exactly what it should be. To demonstrate, if the nucleotide is thymine for the original strand, the new strand should be adenine. <span>However, if the bonding is arbitrary, then the new strand could be cytosine or guanine as well, therefore there is no definite answer to what the new strand should be. This will make havoc in the genetic codes and will most likely kill the organism. 
</span>I hope this answer has answered your question and good luck with your assignment. I apologise if I am incorrect. Have a good day/night. 
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Answer:A,B,D,E,F

Explanation:

Stock can be transfer depending on the organization.

The movement of stock is divide into three broad categories

Stock transfer from Plant to plant- movement of stock from a plant to another plant

Stock transfer from Company code to company code- movement from ome company code to another

Stock transfer from Storage location to storage location

Between different plants within the same storage - stock can be moved from one plant to another within the same storage this will lead to a change in quantity in both plant and it should be noted

Between storage locations within one plant- stock location can be change in a plant but it doesn't affect the quantity.

Between plants in different company code- stock can also be moved from one company code to another this requires adequate documentation when the stocked are moved.

5 0
3 years ago
What is your opinion about minor children (under the age of 18) donating one of their kidneys for their brother or sister? Write
lys-0071 [83]
I think that minor shielded should not donate one of their kidneys because some genetic kidney diseases won’t have started to cause symptoms yet in young children and so it’s hard to know if their kidneys may be affected by diseases
4 0
3 years ago
In addition to tempature and precipitation, koppens climate system classified by a regions
sp2606 [1]

Answer:

sounds hard have a good day

Explanation:

5 0
3 years ago
Researchers want to study behaviors in lions. They
Romashka-Z-Leto [24]

The limitation in the behavior of lions is that the lions living in a group called a pride , in which lions have strong bond and do not accept a stranger.

<h3>What is pride and how lions behave in social lion group?</h3>
  1. A study showed that most of the lions living and sharing same geographical area have friendly behavior.
  2. Pride is a group of lions in which lions interact with each other and share a close bond and do not accept a stranger.
  3. A pride comprises of total thirty lions at max , above which pride is not a group .
  4. Behavior like liking , meowing is amongst the friendly behavior lion shows towards other lion.
  5. The female lions defends the cub , comparatively to the father of the cub.

To know more about lions visit:

brainly.com/question/321742

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6 0
1 year ago
In a hypothetical population of plants, flower color is determined by a single gene with two alleles. In a population of 500 pla
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Answer:

Phenotype genotype Number of individuals

Red RR 245

Pink Rr 210

White rr 45

Number of alleles in total

R = 245 + 245 + 210 = 700 ---> 700/1000= 0.7 R frequency

r = 210 + 45 + 45 = 300 -----> 300/1000 = 0.3 r frequency

Predict (Hardy Weinberg) genotype frequencies=

p^2 + 2pq + q^2 = 1

p= 0.7

q=0.3

0.49 + 0.42 + 0.9 =1

According Punnett Squares in F1 we have=

Rr* rr = Rr 50% and rr 50%

4 0
3 years ago
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