Answer:
The numbers are -14,-13 and -12
Step-by-step explanation:
<u><em>The correct question is </em></u>
Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?
Let
x ----> the first consecutive integer
x+1 ---> the second consecutive integer
x+2 ---> the third consecutive integer
we have that
solve for x
apply distributive property
Combine like terms
subtract 8 both sides
Divide by 6 both sides
so
therefore
The numbers are -14,-13 and -12
Answer:
Option C)
Step-by-step explanation:
The samples are dependant. There should be a relation between the weights of the students, even though there could be changes, as any value can go up or down. A student with a weight around of 30 has a higher chance of getting a weight around of 35 after the firts year than a student with weight around of 55. This means that the probability a student has for getting certain amount of weight after the first year may change depending on the weight the student had at the start of the year. You can therefore naturally relate the weight a student had before the first year with the weight the student had after the first year.
So, the samples are dependant because there is a natural pairing between the to samples, as option C says.
Answer:
3+5n=5(n+2)-7*
We move all terms to the left:
3+5n-(5(n+2)-7*)=0
We calculate terms in parentheses: -(5(n+2)-7*), so:
5(n+2)-7*
We add all the numbers together, and all the variables
5(n+2)
We multiply parentheses
5n+10
Back to the equation:
-(5n+10)
We get rid of parentheses
5n-5n-10+3=0
We add all the numbers together, and all the variables
-7!=0
There is no solution for this equation
Step-by-step explanation:
When the graph rises one square for a run of one square, the slope is 2 km/(0.5 h) = 4 km/h. When the graph rises half that fast, the slope is 2 km/h. When the graph is horizontal, the slope is 0. The slope of the distance vs time curve is the speed.
- S = 4 km/h, when 0 < t < 2 h
- S = 0, when 2 h ≤ t < 2.5 h
- S = 4 km/h, when 2.5 h ≤ t < 3 h
- S = 0, when 3h ≤ t < 4 h
- S = 2 km/h, when 4 h ≤ t < 5 h