All categories

3 years ago

Gary ate 41/50 of his candy bar. What percent of the candy bar did Gary eat? *

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

8 0

1) 82%
2) 1/5
3) 60%
4) 50%
5) 300
6) 18
7) 40
8) 15
9) 112.5
10) 96

ruslelena [56]3 years ago

3 0

1. 82%
2. 1/5
3. 60%
4. 50%
5. 6.75
6. 300
7. 18
8. 40
9. 60
10. 112.5
11. 96

Hope this helps!

You might be interested in

What decimal is equivalent to 41 ?<br> 100

BlackZzzverrR [31]

Answer:

In the fraction 41/100, 41 is the numerator and 100 is the denominator, the fraction bar means "divided by". So to convert 41/100 as decimal number we simply divide the numerator by denominator.

When we calculated 41 divided by 100, we found that 41/100 in decimal form is:

41 ÷ 100 = 0.41

Therefore, the decimal equivalent of 41/100 is 0.41

Step-by-step explanation:

Hope it is helpful....

8 0

3 years ago

Read 2 more answers

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

3 years ago

Please help with this problem?!?

STALIN [3.7K]

Answer:

37.5%

Step-by-step explanation:

3/8=37.5%

Hope this helps! :)

4 0

3 years ago

Read 2 more answers

Which numbers in set ={,,,,,,,,,}eh equals left brace 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10

viva [34]

Answer:

D={3,9}

The numbers are 3 and 9

Step-by-step explanation:

The set A

={,,,,,,,,,}

Let B be the sub set of A containing odd numbers

B={1,3,5,7,9}

Let C be the sub set of A containing multiply of 3

C= {3,6,9}

Now let D be the be the sub set of A containing both odd numbers and multiples of 3

D={3,9}

5 0

3 years ago

Solve the system of equations and choose the correct ordered pair.

nasty-shy [4]

The answer is D

Because if you replace the variables just by testing them they give the answer as X=-3 and Y=3.
In which replacing:
3(-3)+5(3)=6
and with the other equation we've got:
4(-3)+2(3)=-6
so they comply with the required to be the correct answer, even though you can make a system of equation.

6 0

4 years ago