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Simora [160]
3 years ago
14

Gary ate 41/50 of his candy bar. What percent of the candy bar did Gary eat? *

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
1) 82%
2) 1/5
3) 60%
4) 50%
5) 300
6) 18
7) 40
8) 15
9) 112.5
10) 96
ruslelena [56]3 years ago
3 0
1. 82%
2. 1/5
3. 60%
4. 50%
5. 6.75
6. 300
7. 18
8. 40
9. 60
10. 112.5
11. 96

Hope this helps!
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A part of the real number line is shown.
umka2103 [35]
Its R
you can just see in figure as square root of 50 is approximately around 7.07
7 0
3 years ago
What is an equation of the line that passes through the points ( 0,-7) and ( 5, -1)
tresset_1 [31]

Answer:

y = 5/6x - 5.167

Or

y = 5/6x - 31/6

Step-by-step explanation:

The equation of a line

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given points

( 0 , -7) ( 5 , -1)

x1 = 0

y1 = -7

x2 = 5

y2 = -1

Insert the values into the equation

m = -1 - (-7) / 5 - 0

m = -1 + 7 / 5

m = 6/5

y = 6/5x + c

Step 2: sub any of the two points given into the equation

y = 5/6x + c

( 5 , -1)

x = 5

y = -1

-1 = 5/6(5) + c

-1 = 5*5/6 + c

-1 = 25/6 + c.

c = -1 - 25/6

LCM = 6

c = -6 - 25 / 6

c = -31/6

c = -5.167

Step 3: sub c into the equation

y = 5/6x + c

y = 5/6x - 31/6

Or

y = 5/6x - 5.167

The equation of the line is

y = 5/6x - 5.167

7 0
3 years ago
What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?
ikadub [295]
\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=1\\
r=3\\
n=7
\end{cases}
\\\\\\
a_7=1\cdot 3^{7-1}\implies a_7=1\cdot 3^6\implies a_7=1\cdot 729\implies a_7=729
7 0
3 years ago
What is 3 x 2.7 in iReady?
Scrat [10]

Answer:

it's probably 8.1

Step-by-step explanation:

:)

P.S: You could use a calculotor next time

7 0
2 years ago
Read 2 more answers
Use the Remainder Theorem to find the remainder for (2x^3-3x^2+6)/(x-1) and state whether or not the binomial is a factor of the
Bezzdna [24]

Answer:

Remainder= 5, and the binomial (x-1) is not a factor of the given polynomial.

Step-by-step explanation:

Given polynomial is (2x^3-3x^2+6) , we have to divide this with a binomial [tex}(x-1)[/tex] using remainder theorem.

Remainder theorem says if (x-a) is a factor then remiander would be f(a)

Therefore for (x-1), \ {we find}\  f(1)}

f(1)=(2\times 1^3-3\times1^2+6)\\1^3 =1\\1^2=1\\Substituting \ this \ above\\f(1)= (2-3+6)=5

Thus the remainder is 5 and since it is not 0 , so the binomial (x-1) is not a factor of the given polynomial.

6 0
3 years ago
Read 2 more answers
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