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snow_lady [41]
3 years ago
8

Line b and line c are perpendicular at the point (4,2). If the equation of line b is y=2x, what is the equation for line c?

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

The equation of line C would be y = -1/2x + 4

Step-by-step explanation:

To find the equation, we first need to find the slope. Since the original line has a slope of 2 and all perpendicular lines have opposite and reciprocal slopes, we know the new line to have a slope of -1/2.

Now we use that along with the given point in point-slope form.

y - y1 = m(x - x1)

y - 2 = -1/2(x - 4)

y - 2 = -1/2x + 2

y = -1/2x + 4

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bixtya [17]

Answer: C; 3 4/2

Step-by-step explanation:  A fraction exponent can be represented using a radical. The base number is the number in the radical. The numerator of the fraction is the exponent inside the radical. The denominator is the type of radical.

An exponential always crosses at (0,1) This function crosses at (0.6) meaning it has shifted up 5 units or +5. These means only answer options A and D are possible solutions. Also, since the graph starts high and ends low and leveling out, this means the base is less than 1. Only 3/4 is less than 1. Answer A is the solution.

hope this helps, thank you! :)

6 0
3 years ago
Please solve and explain the question below
solong [7]

Answer:

OPTION A

Step-by-step explanation:

To find the table substitute the points on the given function and compare the values.

The given function is: $ y = x^2 + 2 $.

OPTION A:

(i) When x = -2

LHS = y = 6.

RHS = (-2)² + 2 = 4 + 2 = 6.

LHS = RHS

(ii) When x = -1

LHS = y = 3

RHS = (-1)² + 2 = 1 + 2 = 3.

LHS = RHS

(iii) When x = 0

LHS = y = 2

RHS = 0² + 2 = 2.

LHS = RHS

(iv) When x = 1

LHS = y = 3

RHS = (1)² + 2 = 1 + 2 = 3.

LHS = RHS

(v) When x = 2

LHS = y = 6

RHS = (2)² + 2 = 4 + 2 = 6

LHS = RHS

OPTION B:

(i) When x = -2

LHS = y = -2

RHS = (-2)² + 2 = 6

LHS \neq RHS

OPTION B is eliminated.

OPTION C:

(i) When x = -2

Using the same reason as OPTION B this option is eliminated as well.

So, OPTION A is the correct answer.

5 0
3 years ago
What is the distance, in units, between the points <img src="https://tex.z-dn.net/?f=%282%2C%20-6%29" id="TexFormula1" title="(2
Anna71 [15]

Answer: 3\sqrt{13}

Step-by-step explanation:

\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

\sqrt{\left(-4-2\right)^2+\left(3-\left(-6\right)\right)^2}

=3\sqrt{13}

6 0
3 years ago
A quantity with an initial value of 3700 decays exponentially at a rate of 6% every 5
SSSSS [86.1K]

Answer:

2369.86

Step-by-step explanation:

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1 year ago
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