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3 years ago

Line b and line c are perpendicular at the point (4,2). If the equation of line b is y=2x, what is the equation for line c?

Mathematics

1 answer:

Murrr4er [49]3 years ago

3 0

Answer:

The equation of line C would be y = -1/2x + 4

Step-by-step explanation:

To find the equation, we first need to find the slope. Since the original line has a slope of 2 and all perpendicular lines have opposite and reciprocal slopes, we know the new line to have a slope of -1/2.

Now we use that along with the given point in point-slope form.

y - y1 = m(x - x1)

y - 2 = -1/2(x - 4)

y - 2 = -1/2x + 2

y = -1/2x + 4

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3 years ago

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

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