Answer:
Length of string used by Claire = 7 / 3 feet
Step-by-step explanation:
Given:
Length of string Claire in starts =
feet
Length of string Claire in end =
feet
Find:
Length of string used by Claire
Computation:
Length of string Claire in starts =
feet = 25 / 6 feet
Length of string Claire in end =
feet = 11 / 6 feet
Length of string used by Claire = Length of string Claire in starts - Length of string Claire in end
Length of string used by Claire = [25 / 6] - [11 / 6]
BY taking LCM
Length of string used by Claire = [25 - 11] / 6
Length of string used by Claire = 14 / 6
Length of string used by Claire = 7 / 3 feet
20 divided by 1/3 = 6 2/3, therefore Ms Chavez used 6 and two thirds of eggs.
the correct answer would be -5/12
Answer:
first one is 42/7 = 6
11*6 = 66
second one
1/2 inch = 3/2 feet
17/2 inches = 17*3 = 51/2 = 25.5
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²