The estimation for m would be 120. Happy thanksgiving
For this case, the first thing we must do is define variables.
We have then:
x: number of minutes
y: final temperature
We write then the equation that models the problem:
For y = 20 we have:
Clearing x:
Answer:
The temperature of the water will be 20 degree celcius after 150 minutes
Y=mx+b
b= -2
m= rise/run = 2/3
y=2/3x-2
Answer:
8 ================================================================ D
i might be incompetent but at least I'm not impotent
Step-by-step explanation:
Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3
Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2