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Crank
2 years ago
12

In the picture, thanks :)

Mathematics
1 answer:
Mrrafil [7]2 years ago
8 0
Answer is G
2y-x=10
Division by 2 to get rid of it
Y-x=5
Add x to both side to make y to stay alone
Y=x+5
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Veronica has to multiply 398 x 18. She says she can multiply 400 x 18 and then take away one group of 18
vredina [299]
No I don't agree with her because she is wrong and even if you multply 400 times 18 it will give you 7,200
8 0
3 years ago
The perimeter of a rectangle is 52 cm. If its width is 2 cm more than one-third of its length, find the dimensions of rectangle.
Jobisdone [24]

Answer:

(B) 18 cm x 8 cm

Step-by-step explanation:

let the length be x,

then the width is \frac{1}{3}x + 2

2( \frac{1}{3}x + 2 + x ) = 52

\frac{1}{3}x + 2 + x  = 26

\frac{4}{3} x = 24

x = (24*3)/4

x = 18

then the length is 18 cm

and width is (1/3)*18 + 2 = 8

Therefore the dimensions are length:width = 18 cm : 8 cm

7 0
2 years ago
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What is 4y-x+7+5y+3x-9
zimovet [89]

Answer:

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Step-by-step explanation:

If you're just looking to simplify and/or combine like terms, here's your answer: 2 x + 9 y − 2

Glad I could help!!

4 0
2 years ago
How many factors in the number 21 and is the number 21 a Prime or Composite?
anygoal [31]

Answer:

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Step-by-step explanation:

4 0
2 years ago
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Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).
Vanyuwa [196]
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R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R
5 0
2 years ago
Read 2 more answers
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