Ask question

Ask question

All categories

3 years ago

14

In 1990, when the CPI-U was 132.4, the Bucy family spent an average of $80 per week on food. What was their weekly food bill in

1994 for the same type abd amount of food?

1 answer:

timurjin [86]3 years ago

7 0

The answer to your question is 83 on average

You might be interested in

4 1/6 + 5 2/3<br><br> Enter your answer as a mixed number in simplest form

anyanavicka [17]

Answer:9 5/6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Jared is using a 10ft rope

SVEN [57.7K]

Nice;-;

does jared need help carrying it

6 0

3 years ago

A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0

3 years ago

What is the answer to this?

a_sh-v [17]

The answer is 35 bc it has pointed on the dot

5 0

4 years ago

I need some help with this one I'm lost!

SpyIntel [72]

Answer:

-334

Step-by-step explanation:

tyes sfdfa d

3 0

3 years ago