Has to be a fraction. 50 points, don't miss out :-)
1 answer:
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1. Assume the manufacturer produced 100 products.
2. 70 are acceptable and 30 are defective.
3. the first product has a probability of 70/100 to be selected from the acceptable ones. The second 69/99 (one is removed from the good ones) and the third one 68/98
4. so P(pick 3 consecutive acceptable products)=
=0.339
5. If familiar to the Combination formula C(n, r)=
:
P(picking 3 acceptable out of 100)=n(picking 3 acceptable)/n(picking 3)=C(70, 3)/C(100/3)=
= 0.339
2. 70 are acceptable and 30 are defective.
3. the first product has a probability of 70/100 to be selected from the acceptable ones. The second 69/99 (one is removed from the good ones) and the third one 68/98
4. so P(pick 3 consecutive acceptable products)=
5. If familiar to the Combination formula C(n, r)=
P(picking 3 acceptable out of 100)=n(picking 3 acceptable)/n(picking 3)=C(70, 3)/C(100/3)=