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Andru [333]
3 years ago
6

-8h+z/7 Use z=21 and h=4

Mathematics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Hope this helps

Step-by-step explanation:

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5.Matrices M and N are shown below.
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Step-by-step explanation:

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2 years ago
Which function described as the arithmetic sequence below 1,-2,-5,-8,-11
motikmotik

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =
Helen [10]

For the ODE

ty'+2y=\sin t

multiply both sides by <em>t</em> so that the left side can be condensed into the derivative of a product:

t^2y'+2ty=t\sin t

\implies(t^2y)'=t\sin t

Integrate both sides with respect to <em>t</em> :

t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C

Divide both sides by t^2 to solve for <em>y</em> :

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}

Now use the initial condition to solve for <em>C</em> :

y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}

\implies9=\dfrac4{\pi^2}(1+C)

\implies C=\dfrac{9\pi^2}4-1

So the particular solution to the IVP is

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}

or

y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}

6 0
2 years ago
What do I need to multiply or divide to show that the answer I got which was 44.8 right plzzz help part total question
GuDViN [60]
56 times 0.8 I think I might be wrong
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3 years ago
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