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3 years ago

What is 2.9 as a mixed number?

Mathematics

2 answers:

HACTEHA [7]3 years ago

6 0

2.9/1 should be your fraction although Explanation: 2.9 is two and nine tenths. 2.9=2910 as a mixed fraction

lapo4ka [179]3 years ago

3 0

Answer:

2910 ….....................….......

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The weight of 5 children in a boat are 83 pounds, 92 pounds, 88 pounds, 105 pounds, and 86 pounds. What is the average weight, i

suter [353]

The average weight is 90.8 pounds per child.

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4 years ago

Doomtown is 300 miles due west of Sagebrush and Joshua is due west of Doomtown. At 9 a.m. Mr. Archer leaves Sagebrush for Joshua

e-lub [12.9K]

Refer to the diagram shown below.

Let the distance that Sassoon travels is d miles.
Let his average speed be x mph.
The time of travel is from 1 p.m. to 4 p.m., which is 3 hours.
Therefore
3x = d (1)

The distance that Archer travels is (d + 300) miles.
The time of travel is from 9 a.m. to 4 p.m., which is 7 hours.
The average traveling speed is (x + 20) mph, therefore
7(x + 20) = d + 300
That is,
7x + 140 = d + 300
7x = d + 160 (2)

Subtract (1) from (2).
7x - 3x = d + 160 - d
4x = 160
x = 40 mph (Sassoon's average speed)
x+20 = 60 mph (Archer's average speed)
From (1), obtain d = 120 mi

Answer:
Archer's speed is 60 mph.
Sassoon's speed is 40 mph.

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3 years ago

Solve each equation <br><br> r - 5 1/6 = 10 <br><br> please help me Thank youuu!

Charra [1.4K]

[tex}r - 5 \frac{5}6 + 5\frac{5}6 = 10 +5\frac{5}6{/tex] $r=15 \frac{5}6$

5 0

3 years ago

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The height, h, of a ball that is tossed into the air is a function of the time, t, it is in the air. The height in feet for t se

Ivenika [448]

Answer:

e) none

Step-by-step explanation:

The first thing that we need to realise is that this question is set to a practical example of a ball being tossed into the air for a period of time. Thus, we know that:

a) time cannot be negative

b) a ball cannot travel a negative distance in height from where it was tossed it into the air (given that this starting position is also the ground)

In the context of what the problem asks us to achieve, which is to find the domain, we now know that:

a) t ≥ 0

b) the function h(t) is only practical when h(t) ≥ 0

In other words, we know that the domain starts at t = 0, however we need to find when the ball drops back onto the ground. We can do this by solving h(t) = 0:

h(t) = -16t^(2) + 96t

0 = -16t^(2) + 96t

0 = -16t(t - 6) (Factorise -16t^(2) + 96t)

So, now we get:

-16t = 0, therefor t = 0

t - 6 = 0, therefor t = 6

Thus, the ball is on the ground at t = 0 seconds and t = 6 seconds; it is between these two values of t that the domain exists and that the problem is practical.

Now, looking at the multiple choice options, it seems as though none of them are correct, therefor the answer would be e) none.

The other way to work through this question (particularly if it is just multiple choice) is that, after realising that the ball is tossed into the air at t = 0 seconds and then drops at some point later, we could already discount a), b) and c) as answers since they include infinity in the domain, which is not practical for this problem.

Then, we could substitute t = 5 into the equation to get:

h(t) = -16(5)^2 + 96*5

h(t) = -16*5*5 + 96*5

h(t) = -80*5 + 96*5

Since we need h(t) to be 0 at the end value of the domain, this is not the correct answer. Thus, the answer is e) none.

6 0

3 years ago

I NEED HELP ASAP!!!! I DONT UNDERSTAND HOW TO DO This!! Please do step by ste and tell me where it goes thank you

MariettaO [177]

Answer:

Step-by-step explanation:

A: 5600 meters per hour

B: 700 meters per 1/6 hour

C: 4200 meters per hour

I cant see the final question

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3 years ago

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