Respuesta:
3x-y-1 = 0
Explicación paso a paso:
La forma estándar de ecuación de una línea se expresa como y = mx + b
M es la pendiente
b es la intersección con el eje y
Dada la coordenada P1 (2,5) y P2 (4,11)
Pendiente m = y2-y1 / x2-x1
m = 11-5 / 4-2
m = 6/2
m = 3
Sustituya m = 3 y (2,5) en y = mx + b
5 = 3 (2) + b
5 = 6 + b
b = 5-6
b = -1
Obtén la ecuación
y = 3x-1
Igualar a cero
y - 3x +1 = 0
Multiplicar por -1
3x-y-1 = 0
Esto da la ecuación requerida
Answer:
v=a+ 2e1= [3 1 1 1] 
.
Step-by-step explanation:
Let a = 
![\left[\begin{array}{ccc}\\1&1&1\\\end{array}\right] ^{T}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5C%5C1%261%261%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5E%7BT%7D)
and we know that
=±║α║₂= 2.
As we have gone over in class, the formula for v is v= a-e1
with the sign of chosen to avoid subtraction. This gives v=a+ 2e1= [3 1 1 1] .
Disclaimer ;The question is incomplete
Question:
Determine the Householder transformation that annihilates all but the first entry of the vector[1 1 1 1]>Specifically, if
![I-2vv^{T}/v^{T}v\left[\begin{array}{ccc}1\\1\\1\\1\end{array}\right]](https://tex.z-dn.net/?f=I-2vv%5E%7BT%7D%2Fv%5E%7BT%7Dv%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
==![\left[\begin{array}{ccc}\alpha \\0\\0\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Calpha%20%5C%5C0%5C%5C0%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
what are the values of α and v?
#SPJ4
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Step-by-step explanation:
