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atroni [7]
3 years ago
11

Interior angels that lie on opposite sides of transversel are called

Mathematics
1 answer:
lesya [120]3 years ago
5 0

they are called co-interior angles

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-4 plus the square root of 81​
almond37 [142]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The square root of 81 is 9

We have -4 + 9

Thus, your answer is 5

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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6 0
3 years ago
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Can someone help me with this? Plz.<br><br> Solve the quadratic equation 2x^2-4x-1=0
Mila [183]
You have to use the quadratic formula to solve this. The zeros of this quadratic are 2 + sqrt2/2 and 2 - sqrt2/2, which in "real" numbers is 1.707 and .2928
6 0
3 years ago
In a triangle, the measure of the first angle is twice the measure of the second angle. The measure of the third is 92° more tha
lesya692 [45]

Answer:

The measure of first angle is 44°.

The measure of second angle is 22°.

The measure of third angle is 114°.

Step-by-step explanation:

First, you have to form expressions for the 3 angles. Let second angle be x :

First angle = (2x)°

Second angle = x°

Third angle = (92 + x)°

Next, you have to add up altogether as the total angles in a triangle is 180° :

2x + x + 92 + x = 180

4x + 92 = 180

4x = 180 - 92

4x = 88

x = 88 ÷ 4

x = 22°

Lastly, you have to substitute the x-value into the expressions :

First angle = 2(22) = 44°

Second angle = 22°

Third angle = 92 + 22 = 114°

7 0
4 years ago
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Name the circle part L shown in the figure.<br><br> O Arc<br> O Sector<br> O chord<br> O radius
Gemiola [76]

Answer:

Step-by-step explanation:

6 0
3 years ago
Find the equation of a sphere if one of its diameters has endpoints: (-9, -12, -6) and (11, 8, 14).
baherus [9]

Answer:

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

Step-by-step explanation:

There are two kew parameters for a sphere: Center (h, k, s) and Radius (r). The radius is the midpoint of the line segment between endpoints. That is:

C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2}   \right)

C(x,y,z) = (1,-2,4)

The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:

r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}

r = 10\sqrt{3}

The general formula of a sphere centered at (h, k, s) and with a radius r is:

(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

8 0
3 years ago
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