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Jet001 [13]
3 years ago
9

Professor Halen has 184 students in his college mathematics lecture class. The scores on the midterm exam are normally distribut

ed with a mean of 72.3 and a standard deviation of 8.9. How many students in the class can be expected to receive a score between 82 and 90?
Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer: 21

Step-by-step explanation:

Given : The scores on the midterm exam are normally distributed with

\mu=72.3\\\\\sigma=8.9

Let X be random variable that represents the score of the students.

z-score: z=\dfrac{x-\mu}{\sigma}

For x=82

z=\dfrac{82-72.3}{8.9}\approx1.09

For x=90

z=\dfrac{90-72.3}{8.9}\approx1.99

Now, the probability of the students in the class receive a score between 82 and 90 ( by using standard normal distribution table ) :-

P(82

Now ,the number of students expected to receive a score between 82 and 90 are :-

184\times0.1146=21.0864\approx21

Hence, 21 students are expected to receive a score between 82 and 90 .

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Answer:

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Step-by-step explanation:

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8 0
4 years ago
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If LW = 5x + 2 and LJ = 11x + 2 in the parallelogram below. Find LW.
WITCHER [35]

Answer:

A. 12

Step-by-step explanation:

Recall: one of the properties of a parallelogram is that the diagonals bisect each other. This means that:

LJ = 2(LW)

11x + 2 = 2(5x + 2)

11x + 2 = 10x + 4

11x + 2 - 2 = 10x + 4 - 2

11x = 10x + 2

11x - 10x = 10x + 2 - 10x

x = 2

✅LW = 5x + 2

Plug in the value of x

LW = 5(2) + 2

LW = 10 + 2 = 12

3 0
3 years ago
Is 3/2 greater than 1.hurry i nee a response
ICE Princess25 [194]

Answer:

Yes

Step-by-step explanation:

3/2 = 1.5

1.5 > 1

Best of Luck!

7 0
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If the diagonals of a quadrilateral bisect the angles, is the quadrilateral always a parallelogram? Explain your answer.
Liula [17]
Yes. If the diagonals bisect the angles, the quadrilateral is always a parallelogram, specifically, a rhombus.


Consider quadrilateral ABCD. If diagonal AC bisects angles A and C, then ΔACB is congruent to ΔACD (ASA). Hence AB=AD and BC=CD (CPCTC).

Likewise, if diagonal BD bisects angles B and D, triangles BDA and BDC are congruent, thus AB=BC and AD=CD. (CPCTC again). Now, we have AB=BC=CD=AD, so the figure is a rhombus, hence a parallelogram.
6 0
3 years ago
Malorie took out a loan to build a deck.The loan was for $15000 and had a 7.5% simple interest rate. If she paid a total of $1,6
attashe74 [19]

Answer:

  • The final value (FV)  that is paid in a loan (which is the sum of the capital and the interests) equals the present value (PV) of the loan  multiplied by (1+i\times{n}), in a simple interest context, where "n" equals the periods of time and "i" equals the interest rate valid for that periodicity.
  • Then FV=PV\times(1+i\times{n}). In this case, PV=$15,000; final value equals FV=$15,000+1,687.5= $16,687.5.
  • We should clear "n" from our equation, which means: 16,687.5=15,000\times(1+n\times0.075). Dividing both sides by 15,000, then subtracting 1 both sides, and finally dividing by 0.075 both sides, results in n=1.5.
  • Then, Malorie had the loan for one an a half periods.

3 0
3 years ago
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