A^2+b^2=c^2
32^2+b^2=125^2
1024+b^2=15625
-1024 -1024
b^2=14601
√b^2=√14601
b=120.834598
Therefore the length if the leg is about 120.8 units long
We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is

but this would imply that

, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".
Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have

and solving gives

, which makes more sense. Then the number of extra spades in the deck must be 2.
Hello!Your answer is

If you use a calculator and divide 23 by 99, you will get 0.232323............
Answer ⇒
Amount = 3,700 * (1.0475)^9
<span><span>Amount = 3,700 * 1.5184003135
</span>
</span><span>Amount =
</span><span><span><span>5,618.08
</span>
</span>
</span>
y =-3x + x + 9
Find y when x = 2
Substitute the value of x= 2 into the equation
y = -3(2) + 2 + 9
y = - 6 + 2 + 9
y = -4 + 9
y = 5
The answer is 5