Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer:
weres the answer how am i going to answer this
Step-by-step explanation:
Answer: 7
Step-by-step explanation:
Factors of 7 are, 1, and 7. The factors of 21 are, 1, 3, 7, and 21, making 7 the gcf.
Okay Let's say
2x + 3 = 45
-3 -3
----------------
2x = 42
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2 2 x = 21
Y - ,2.5
X 0,3.5
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