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DedPeter [7]
3 years ago
7

The school that Joe goes to is selling tickets to a choral performance. On血e first day of ticket

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

The price of one senior citizen ticket is $8, and the price of one child ticket is $11.

Step-by-step explanation:

You are looking for two things: the price of a senior citizen ticket and the price of a child ticket.

We need to write two equations using two variables.

Let s = price of 1 senior citizen ticket.

Let c = price of 1 child ticket.

First day of ticket sales:

6 senior citizen tickets, 8 child tickets, total sales of $136

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 8 tickets cost 8c.

The total sales is 6s + 8c.

The total sales is $136, so our first equation is

6s + 8c = 136

Now we do the same for the second day of ticket sales.

6 senior citizen tickets, 9 child tickets, total sales of $147.

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 9 tickets cost 9c.

The total sales is 6s + 9c.

The total sales is $147, so our second equation is

6s + 9c = 147

The system of equations is

6s + 8c = 136

6s + 9c = 147

Multiply both sides of the first equation by -1. Write the second equation below it. Then add the equations.

       -6s - 8c = -136

(+)     6s + 9c = 147

----------------------------

                  c =   11

c = 11, so the cost of a child ticket is $11.

Now substitute 11 for c in the first equation, and solve for s.

6s + 8c = 136

6s + 8(11) = 136

6s + 88 = 136

6s = 48

s = 8

The price of a senior citizen ticket is $8.

The price of a senior citizen ticket is $8, and the price of a child ticket is $11.

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Samantha's age is 3 years more than half her uncle's age. If her uncle's age is z years, which of the following expressions best
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Step-by-step explanation:

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4 years ago
A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

C = Children; S = Students; A = Adults

For the capacity, we have:

C + S + A = 329

For the tickets sold, we have:

5C + 7S + 12A = 2388

Half as many as adults are children implies that:

A = \frac{C}{2}

Required

Solve for A, C and S

The equations to solve are:

C + S + A = 329 -- (1)

5C + 7S + 12A = 2388 -- (2)

A = \frac{C}{2} -- (3)

Make C the subject in (3)

C = 2A

Substitute C = 2A in (1) and (2)

C + S + A = 329 -- (1)

2A + S + A = 329

3A + S = 329

Make S the subject

S = 329 - 3A

5C + 7S + 12A = 2388 -- (2)

5*2A + 7S + 12A = 2388

10A + 7S + 12A = 2388

7S + 22A = 2388

Substitute S = 329 - 3A

7(329 - 3A) + 22A = 2388

2303 - 21A + 22A = 2388

2303 +A = 2388

Solve for A

A = 2388 - 2303

A = 85

Recall that: C = 2A

C = 2 * 85

C = 170

Recall that: S = 329 - 3A

S = 329 - 3 * 85

S = 329 - 255

S = 74

Hence, the result is:

C = 170

S = 74

A = 85

8 0
3 years ago
The sequence {an} is defined by a0 = 1 and
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The solution to the problem is as follows:

Just plug in the numbers and follow the pattern. 

a0 = 1 

a1 = 2*1 + 2 = 4 

a2 = 2*4 +2 = 10 

<span>a3 = 2*10 +2 = 22
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
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