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Dimas [21]
3 years ago
6

I need help with this question?????

Mathematics
1 answer:
den301095 [7]3 years ago
8 0
18.84

Since the formula of circumference is C = 2 pi r or C = pi times diameter, you can conclude that the circumference is 18.84.

Assuming that pi is 3.14 in this case rather than the full pi or just in terms of pi.

Hope this helps!
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rusak2 [61]
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3 years ago
Simplify the expression 8y+y-5y
IRINA_888 [86]

Hello

8y+y-5y = 9y- 5y =4y

or  8y+y-5y = y(8+1-5) =y (9-5)  = y(4) =4y

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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
3 years ago
What is the value of Negative 4 squared + (5 minus 2) (negative 6)? –34 –2 10 34
kaheart [24]

Answer:

The Answer is -34 (Negative 34)

Letter Choice A

Step-by-step explanation:

Hope it helped!!

7 0
3 years ago
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