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4 years ago

Describe the transformation's necessary to transform the graph f(x) into that of g(x)

Mathematics

1 answer:

slamgirl [31]4 years ago

6 0

Answer:

C and F

Step-by-step explanation:

Those two just work, that simple

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The set of three lengths that will form a right triangle are

Bad White [126]

Answer:

O 16,30,34

Step-by-step explanation:

To confirm, use Pythagorean theorem to check.

(16)² + (30)² = (34)²

256 + 900 = 1156

=> It is correct

=> Therefore, this set of three lengths will form a right triangle

7 0

3 years ago

Please help x 15 points

katovenus [111]

A(0,-1)
B(3√3/3, 2)

Slope of AB = (y₂ - y₁)/(x₂-x₁)
Slope = (2-1)/(√3/3 , -0)

Slope = 1/√3/3 = 1/√3 = √3/3

OR SLOPE = tan(a°) = √3/3 and a° = 30°

3 0

4 years ago

A line connecting a vertex of a scalene triangle with the midpoint of the opposite side is the

Irina18 [472]

The line would be called the median. The definition of '<span>A line connecting a vertex of a scalene triangle with the midpoint of the opposite side' pertains to the median. There are three medians that connect the scalene triangle. </span>

4 0

3 years ago

If f(x) = 2(x)^2 + 5 square root (x+2), complete the following statement (round your answer to the nearest hundredth): f(2) =

mojhsa [17]

$f(x) = 2(x)^{2} +5 \sqrt{x+2}$

$f(2) = 2(2)^{2} + 5 \sqrt{(2)+2}$

$f(2) = 2(4) + 5\sqrt{4}$

$f(2) = 8 + 5(2)$

$f(2)= 8+10$

f(2) = 18

3 0

3 years ago

I need help with this

andre [41]

Answer:

$f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}$

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

Taken altogether, these factors give us the function ...

$\boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}$

8 0

3 years ago