Answer: 2790 students
Step-by-step explanation: With the given information, you could set up a ratio of 30/2 = x/186. When you cross multiply that, you get 2790.
Answers: perpendicular bisector; image
- The reflection of a point P across a line m is the point P' if line m is the <u> perpendicular bisector </u> of segment PP'
- Point P' is called the <u> image </u> of point P.
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Explanation:
If we were to reflect point P over line m to land on P', then we've gone from pre-image to image.
Let's say that Q is the point on segment PP' and it's also on line m. We consider Q the midpoint of segment PP' which means PQ and P'Q are the same length. This indicates P and P' are the same distance away from the mirror line, and that point Q bisects segment PP'. Also, line m is perpendicular to segment PP'. So that's where the "perpendicular bisector" comes from.
It depends on the information you are given. If you are given the measure of the arc created by the angle then that measure is equal to the central angle....maybe if you had a specific question i could help with..? There are various ways to find central angles. It depends.
Answer:
The range of crying times within 68% of the data is (5.9, 8.1).
The range of crying times within 95% of the data is (4.8, 9.2).
The range of crying times within 99.7% of the data is (3.7, 10.3).
Step-by-step explanation:
According to the Empirical Rule in a normal distribution with mean µ and standard deviation σ, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be broken into three parts:
- 68% data falls within 1 standard deviation of the mean. That is P (µ - σ ≤ X ≤ µ + σ) = 0.68.
- 95% data falls within 2 standard deviations of the mean. That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95.
- 99.7% data falls within 3 standard deviations of the mean. That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.
The mean and standard deviation are:
µ = 7
σ = 1.1
Compute the range of crying times within 68% of the data as follows:
The range of crying times within 68% of the data is (5.9, 8.1).
Compute the range of crying times within 95% of the data as follows:
The range of crying times within 95% of the data is (4.8, 9.2).
Compute the range of crying times within 99.7% of the data as follows:
The range of crying times within 99.7% of the data is (3.7, 10.3).